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3 years ago

Which numbers are the extremes of the proportion 3/4=6/8

Mathematics

2 answers:

ki77a [65]3 years ago

8 0

Answer:it’s 3 and 8

Step-by-step explanation:

Lilit [14]3 years ago

8 0

Answer:3/8

Step-by-step explanation:

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Answer options 2 3 4 5

777dan777 [17]

Answer:

k = 5

Step-by-step explanation:

given f(x) then f(x) + k represents a vertical translation of f(x)

• If k > 0 then a shift of k units up

• If k < 0 then a shift of k units down

f(x) crosses the y- axis at - 2

g(x) crosses the y- axis at 3

Thus g(x) is 5 units vertically up from f(x)

since g(x) = f(x) + k → then k = 5

7 0

3 years ago

X^2 + x - 56 = 0 Solve for x

NISA [10]

Answer: x = 7 or x = -8

x² + x - 56 = 0

⇔ x² + 8x - 7x - 56 = 0

⇔ x(x + 8) - 7(x + 8) = 0

⇔ (x - 7)(x + 8) = 0

⇔ x - 7 = 0

or x + 8 = 0

⇔ x = 7 or x = -8

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

If 7x = AB, then AB = 7x Statement Reason

Schach [20]

Answer:

Yes

Step-by-step explanation:

Because they are the same equations, just flipped. hope this helped

8 0

3 years ago

Simplify. −38+(1+22)2

Hitman42 [59]

It would be 3 over 5

4 0

3 years ago