Question

A certain car is capable of accelerating at a uniform rate of 0.85 m/s^2. What is the magnitude of the car's displacement as it accelerates uniformly from a speed of 83 km/h to one of 94km/h?

Answer 1

Solution: 85.11 m

Given:

acceleration of the car, $a= 0.85 m/s^{2}$

initial velocity,$u=83km/h=23.05 m/s$

final velocity, $v=94 km/h=26.11 m/s$

we need to find the displacement (s) of the car.

we would use the equation of motion:

$2as=v^{2}-u^{2}\\ \Rightarrow s=\frac{v^{2}-u^{2}}{2a} \\ \Rightarrow s=\frac{26.11^{2}-23.05^{2}}{2\times0.85}\\ \Rightarrow s=85.11 m$

hence, the displacement done by the car is = 85.11 m