a 0.04kg ball tied to a string moves in a circle that has a radius of 0.70 m. If the ball is accelerating 43.2m/s, what is the t
1 answer:
Answer:
Tangential Velocity = 30.24 m/s
Explanation:
Given that,
Mass of ball, m = 0.04 Kg
Length of the string, r = 0.70 m
Acceleration of the ball, a = 43.2 m/s²
The tangential velocity of ball, V = ?
The centripetal force is given by the relation
Fc = mV²/r newton
where, m - mass of body
V - tangential velocity of body
r - radius of the trajectory
Force applied on the ball to rotate on a circular path
F = m x a newton
The applied force is equal to centripetal force.
So, equalizing the force equations
m x a = m V²/r
Therefore
V² = a x r
V =
Substituting the values
V =
V = 30.24 m/s
So, the tangential velocity of the ball is 30.24 m/s
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Answer:
A.The vertical velocity is constantly increasing as the ball falls.
B.The horizontal velocity does not noticeably change as the ball falls.
G.The horizontal velocity does not affect how long it will take the ball to fall to the floor.
H.The velocity vector of the ball changes as it travels through the air.
Explanation:
As the ball is projected horizontally so here the vertical component of the velocity is zero
So the time to reach the ground is given as
so we will have
so this is the same time as the ball is dropped from H height
Since there is no force in horizontal direction so its horizontal velocity will always remain constant while vertical velocity will change at constant rate which is equal to acceleration due to gravity.
So overall the velocity vector will change due to net acceleration g