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Tanya [424]
4 years ago
12

Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

1031W and has a surface temperature of 11,000 K. Assume that the star is spherical. Use σ=5.67×10−8W/m2⋅K4 for the Stefan-Boltzmann constant and express your answer numerically in meters to two significant figures.
Physics
1 answer:
Lera25 [3.4K]4 years ago
7 0

Answer:

r=5.1\times10^{10}m

Explanation:

The Stefan–Boltzmann law for a black body (as stars are treated) can be written as j^*=\sigma T^4, where j^* is the total energy radiated per unit surface area across all wavelengths per unit time, T the absolute temperature and \sigma=5.67\times10^{-8} Wm^{-2}K^{-4} is the Stefan–Boltzmann constant.

If we multiply j* by the surface area A of the star we get the total energy radiated across all wavelengths per unit time, which is the total power radiated, so we can write:

P=Aj^*=A\sigma T^4=4\pi r^2\sigma T^4

where we have used the formula for the surface area of a sphere A=4\pi r^2

Solving for r we have:

r=\sqrt{\frac{P}{4\pi \sigma T^4}}=\sqrt{\frac{2.7\times10^{31}W}{4\pi (5.67\times^{-8}Wm^{-2}K^{-4})(11000K)^4}}=5.1\times10^{10}m

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It is a solid when is frozen and a liquid when it melts
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A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
3 years ago
Find the force on an object which has the mass of 20kg and an acceleration of 10m/s
Elis [28]

Answer:

200 Newtons

Explanation:

20 kg x 10 m/s squared

4 0
3 years ago
In just 0.30 s , you compress a spring (spring constant 5000 n/m ), which is initially at its equilibrium length, by 4.0 cm. par
Ierofanga [76]
The average power output is the ratio between the work done to compress the spring, W, and the time taken, t:
P= \frac{W}{t} (1)

The work done is equal to the elastic energy stored by the compressed spring:
W=U= \frac{1}{2}kx^2
where k=5000 N/m is the spring constant and x=4.0 cm=0.04 m is the compression of the spring. If we substitute the numbers, we find:
W= \frac{1}{2}(5000 N/m)(0.04 m)^2=4 J

And now we can use eq.(1) to calculate the average power output:
P= \frac{W}{t}= \frac{4 J}{0.30 s}  =13.3 W
7 0
3 years ago
A gyroscope slows from an initial rate of 32.0 rad/s at a rate of 0.700 rad/s2. How long does it take to come to rest? How many
Darya [45]

Answer:

t=45.7s

\alpha =116revolutions

Explanation:

Since we have given values of ω₀=32.o rad/s ,ω=0 and α=-0.700 rad/s² to find t we use below equation

w=w_{o}+at\\  0=(32.0rad/s)+(-0.700rad/s^{2} )t\\t=\frac{-32.0}{-0.700} \\t=45.7s

To find revolutions we use below equation

w^{2}=w_{o}^{2}+2a\alpha

Substitute the given values to find revolutions α

So

0=(32.0rad/s)^{2}+2(-0.700rad/s^{2} )\alpha  \\\alpha =\frac{(-32.0rad/s)^{2}}{2(-0.700rad/s^{2} )} \\\alpha =731rad

To convert rad to rev:

\alpha =(731rad)*(\frac{1rev}{2\pi rad} )\\\alpha =116revolutions

7 0
4 years ago
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