Which of the following is a terrestrial planet on which one would observe the Sun rising in the west and setting in the east?

A ray of light contains two colors: red with wavelength of 660 nm and blue with wavelength 470 nm. The ray passes through two na

densk [106]

Answer:

The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.

Explanation:

Given that,

Wavelength of red = 660 nm

Wavelength of blue = 470 nm

Separated d= 0.30 mm

Distance between screen and slits D= 5.0 m

We need to calculate the distance for red wavelength

Using formula for distance

$y=\dfrac{\lambda D}{d}$

Where, D = distance between screen and slits

d = separation of slits

Put the value into the formula

$y=\dfrac{660\times10^{-9}\times5.0}{0.30\times10^{-3}}$

$y=11\ mm$

For blue wavelength,

Put the value into the formula again

$y'=\dfrac{470\times10^{-9}\times5.0}{0.30\times10^{-3}}$

$y'=7.83\ mm$

We need to calculate the distance on the screen between the first-order bright fringes for each wavelength

Using formula for distance

$\Delta y=y-y'$

$\Delta y=11-7.83$

$\Delta y=3.17\ mm$

Hence, The distance on the screen between the first-order bright fringes for each wavelength is 3.17 mm.

4 0

3 years ago

(33%) Problem 3: Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1100 kg and i

expeople1 [14]

Answer:

The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

Explanation:

Given that,

Mass of first car = 1100 kg

Velocity of first car = 8.5 m/s

Mass of second car = 650 kg

Velocity of second car = 17.5 m/s

Suppose we need to find the final velocity of the cars and direction of the cars.

We need to calculate the velocity of the car in west direction

Using conservation of momentum in west direction

$m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{x}$

$v_{x}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}$

Put the value into the formula

$v_{x}=\dfrac{1100\times0+650\times17.5}{1100+650}$

$v_{x}=6.5\ m/s$

We need to calculate the velocity of the car in south direction

Using conservation of momentum in south direction

$m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{y}$

$v_{y}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}$

Put the value into the formula

$v_{y}=\dfrac{1100\times8.5+650\times0}{1100+650}$

$v_{y}=5.3\ m/s$

We need to calculate the final velocity of the cars

Using formula of velocity

$v_{eq}=\sqrt{(6.5)^2+(5.3)^2}$

$v_{eq}=8.38\ m/s$

We need to calculate the direction

Using formula of direction

$\tan\theta=\dfrac{v_{y}}{v_{x}}$

Put the value into the formula

$\tan\theta=\dfrac{5.3}{6.5}$

$\theta=\tan^{-1}(\dfrac{5.3}{6.5})$

$\theta=39.1^{\circ}$

Hence, The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

8 0

3 years ago

Which of the following is the same size as Pluto?

coldgirl [10]

I would say it's <span>C. the Moon
</span>

4 0

3 years ago

Read 2 more answers

What is the speed of a bobsled whose distance-time graph indicates that it traveled 114m in 30s? m/s

Kitty [74]

3.8 m/s
--------------

5 0

3 years ago

A bicycle wheel rotates at a constant 25 rev/min. What is true about its angular acceleration?

Nostrana [21]

Answer:

The angular acceleration is zero

Explanation:

When an object is in rotational motion, it has a certain angular velocity, which is the rate of displacement of its angular position.

This angular velocity can change or remain constant - this is given by the angular acceleration, which is:

$\alpha =\frac{\Delta \omega}{\Delta t}$

where

$\Delta \omega$ is the change in angular velocity

$\Delta t$ is the time elapsed

Therefore, the angular acceleration is the rate of change of angular velocity.

In this problem, the bicycle rotates at a constant angular velocity of

$\omega=25 rev/min$

This means that the change in angular velocity is zero:

$\Delta \omega=0$

And so, that the angular acceleration is zero:

$\alpha=0$

8 0

3 years ago