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3 years ago

NEED HELP PLEASE ASAP Given: AEDFG AABF

Mathematics

1 answer:

Serggg [28]3 years ago

8 0

Answer:

H-L Theorem

Step-by-step explanation:

They tell you that they are right triangles, and you have your congruency marks. If they never had right angle indicators, this theorem would never work.

I hope this helps you out, and as always, I am joyous to assist anyone at any time.

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Write 22,22 as a fraccion

PtichkaEL [24]

Answer:

1/1

Step-by-step explanation:

22/22 =1

6 0

2 years ago

Read 2 more answers

Daniel has a set off green,blue, and red the red marblesmmake up exactly 1halfs of the set the set has 2 blue marble the number

Blizzard [7]

Answer:

There are 12 marbles in Daniel's set.

Step-by-step explanation:

Given:

Daniel has a set off green,blue and red.

The red marbles make up exactly half of the set.

The set has 2 blue marbles.

The green marbles in set are as twice of the blue marbles in set.

Now, to find the number of marbles in Daniel's set.

Let the number of marbles in Daniel set be $x.$

So, the red marbles = $\frac{1}{2}\ of\ x$ $=\frac{x}{2}$

Blue marbles = 2.

And the green marbles = $2\times 2$ $=4.$

According to question:

$x=\frac{x}{2} +2+4$

$x=\frac{x}{2} +6$

$x=\frac{x+12}{2}$

Multiplying both sides by 2 we get:

$2x=x+12$

Subtracting both sides by $x$ we get:

$x=12.$

Therefore, there are 12 marbles in Daniel's set.

7 0

4 years ago

Solve the problem. How many ways can an IRS auditor select 5 of 10 tax returns for an audit?

marusya05 [52]

Answer:

(12 * 11 * 10 * 9 * 8) / (5 * 4 * 3 * 2 * 1) = 792

Step-by-step explanation:

5 0

3 years ago

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(x+7)/(x^2-49) find the domain. show work

harina [27]

$\large\begin{array}{l} \textsf{Find the domain of}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-49}}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-7^2}}\\\\\\ \textsf{Factor out the denominator using special products:}\\\\ \textsf{(a difference of squares)}\\\\ \mathsf{f(x)=\dfrac{x+7}{(x+7)(x-7)}} \end{array}$

$\large\begin{array}{l} \textsf{Restrictions for the domain:}\\\\ \bullet~~\textsf{Denominators must not be zero:}\\\\ \mathsf{(x+7)(x-7)\ne 0}\\\\ \begin{array}{rcl} \mathsf{x+7\ne 0}&~\textsf{ and }~&\mathsf{x-7\ne 0}\\\\ \mathsf{x\ne -7}&~\textsf{ and }~&\mathsf{x\ne 7} \end{array} \end{array}$

$\large\begin{array}{l} \textsf{Therefore, the domain of f is}\\\\ \mathsf{D_f=\{x\in\mathbb{R}:~~x\ne -7~~and~~x\ne 7\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_f=\mathbb{R}\setminus\{-7,\,7\}}\\\\\\ \textsf{or using the interval notation}\\\\ \mathsf{D_f=\left]-\infty,\,-7\right[\,\cup\,\left]7,\,+\infty\right[.} \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2155752

$\large\textsf{I hope it helps. :-)}$

Tags: function domain real rational factorizing special product interval

7 0

3 years ago

Caleb bought 5 packs of pencils for 10$ . how muc will he pay for 9 packs of pencils?

alexandr402 [8]

Step-by-step explanation:

Find 1 pack of pencil:

1 pack = 10 ÷ 5 = $2

9 packs = 2 x 9 = 18

Answer: $18

3 0

3 years ago