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Sonja [21]
2 years ago
11

NEED HELP PLEASE ASAP Given: AEDFG AABF

Mathematics
1 answer:
Serggg [28]2 years ago
8 0

Answer:

H-L Theorem

Step-by-step explanation:

They tell you that they are right triangles, and you have your congruency marks. If they never had right angle indicators, this theorem would never work.

I hope this helps you out, and as always, I am joyous to assist anyone at any time.

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Can someone please I really don’t understand no one is answering please help
trasher [3.6K]
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8 0
2 years ago
Line segment AB is dilated to create line segment A’B’ using point Q as the center of dilation what is the scale factor
Alex777 [14]

Answer:

2

Step-by-step explanation:

We are given the distance QA=1.25 and QA'=2.5.

We make the relation 2.5/1.25=2 is the scale factor!

5 0
3 years ago
 Solve the system of inequalities and indicate all the integers which are in the solution set:
elena-s [515]
1.) a>10
2.) a<3.5
How I got it: 1.) Subtract 3 from both sides, leaving -2a<10.
2.) Divide by -2 from both sides, remember to flip the inequality sign when dealing with negatives. This leaves you with a>10.
For number 2.) I divided both sides by 5, leaving a<3.5, though this answer may be wrong.
8 0
3 years ago
2. Describe the means-extremes property.
GREYUIT [131]

Step-by-step explanation:

For example:

Ex: 2:3 :: 6:9

In this question, the means are 3 and 6.

The extremes are 2 and 9.

We use this method to find whether the two ratios are equal or not.

We multiply the means and the extremes, and if there products are same, then these two ratios are proportional.

If these two ratios are proportional, their "means" = "extremes"

=> Means = Extremes

=> 3 x 6 = 2 x 9

=> 18 = 18

So, these two ratios are proportional.

Hope this helps you.

8 0
3 years ago
Calculate the value of P and of Q that satisfy the following simultaneous linear equations.
luda_lava [24]

  1. 0.5p -3q =11
  2. 5p +6q =2

1) ×-2

--> 3. -p +6q =-22

2) - 3)

6p =24

p =4

sub into 2)

5(4) +6q =2

20 +6q =2

6q =2 -20 =-18

q=-3

5 0
3 years ago
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