<u>125</u> is the total number of neutrons in an atom of 207/82 Pb
207 - 82 = 125
207 represents the mass number of the atom while 87 represent the atomic number. The mass number is usually the sum of the protons and neutrons in the nucleus.
Explanation:
Atoms of elements are usually classified by their proton number. A change in the proton number changes the element. However, the neutron number of an element can differ within a small range giving various isotopes of the element. Some will be stable others will be less stable. The less stable are less common to occur naturally because they decay.
Usually, for smaller atoms, the number of neutrons is more or less similar to the number of protons. However, with larger atoms, there are more neutrons than protons.
Learn More:
For more on atomic and mass numbers check out;
brainly.com/question/1619702
brainly.com/question/13649517
brainly.com/question/11837355
brainly.com/question/2301068
#LearnWithBrainly
The acceleration of Moby is 2 m/s²
<u>Explanation:</u>
Given:
Time, t = 5 seconds
Velocity, v = 10 m/s
Acceleration ,a = ?
We know:
On substituting the value we get:
Therefore, the acceleration of Moby is 2 m/s²
Answer:
The CORRECT answer is A OR B
Explanation:
Answer:
your answer would be
A.predict the genotypic and phenotypic probabilities of possible offspring
Answer:-3463 kJ and -3452kJ
Explanation:
ΔU is the change in internal energy of a system and its formula is;
ΔU = q + w
Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.
W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.
For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.
Therefore,
ΔU = -q-w
ΔU = -3452 kJ – 11kJ
= - 3463kJ
ΔH is the change in the enthalpy of a system and its formuls is;
ΔH = ΔU + Δ(PV)
By product rule Δ(PV) becomes ΔPV + PΔV
At constant pressure ΔP = 0. Therefore,
ΔH = -q-w + PΔV
w is equals to PΔV, So:
ΔH = -q
ΔH = -3452kJ
