Had to look for the options and here is the answer. The concentration of glucose carriers in which the glucose concentration is being decreased to zero is 400. This level is already classified as above normal of the rate of glucose concentration. Hope this helps.
We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of
we have to dilute??
It's simple.
Using a periodic table we can find the molar mass of
Then
now we can replace it
Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
Answer:
True
Explanation:
When a base is dissolved in water, the balance between hydrogen ions and hydroxide ions shifts the opposite way. Because the base "soaks up" hydrogen ions, the result is a solution with more hydroxide ions than hydrogen ions. This kind of solution is alkaline.
Answer:
Explanation:
1...............
CoCl₂ is an ionic compound
CF₄ is molecular
BaSO₄ is an ionic compound
NO is molecular
An ionic compound is a compound which forms between a metal and non-metal. It involves the formation of a bond between two ions of significant electronegative difference. It results from the electrostatic force of attraction between two atoms in which one has lost an electron(metal) and the other that has gained an electron(non-metal).
CoCl₂ is an ionic compound
BaSO₄ is also ionic
A molecular compound is formed as a result of covalent bonds between atoms. This is due to the fact that the two atoms have similar electronegativities and would both pull the shared electrons closely. Most molecules are usually formed this way.
CF₄ and NO are both molecular compounds
2...... The ionic compounds are the ones containing metals:
In CoCl₂ the metal is Co, cobalt
BaSO₄ has Ba
Co is a transition metal. Transition elements are known to have various oxidation states. This implies that they can form more than one type of ion. The oxidation number of Co are -1, 0, +1, +2, +3 and +4
Ba will only form one type of ion as an alkaline earth metal. It has an oxidation state of +2 only. It will only form one type of ion.
Answer:
520mL
Explanation:
Data obtained from the question include:
Molarity of stock solution (M1) = 12M
Volume of stock solution (V1) = 130mL
Molarity of diluted solution (M2) = 3M
Volume of diluted (V2) =..?
The volume of the diluted solution can be obtained as follow:
M1V1 = M2V2
12 x 130 = 3 x V2
Divide both side by 3
V2 = 12 x 130 / 3
V2 = 520mL.
Therefore, 520mL of the diluted solution can be prepared.
