Answer:
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
Step-by-step explanation:
Because it is a equilateral triangle, it means all sides have the same length.
AB = AC
5/4 y - 1 = 7/3 y - 2
5/4 y - 7/3 y = -2 +1
-13/12 y = -1
y = 12/13
input y to the equation.
AB = 5/4 y - 1 = 5/4 (12/13) -1 = 2/13
AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13
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Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and
Bond [772]
Answer:
c
Step-by-step explanation:
4/52 + 4/52 = 8/52 or 4/13
Answer:
1. 0.8 cm
2. 1.6 cm
Step-by-step explanation:
1.
The scale for 2nd map is 1 cm to 50 km, that means "1 cm on map" is "50 km in real life".
We already know distance from Cleveland to Cincinnati is 40 km, which is less than 50, so we know the distance on map would be less than 1 cm.
So we set up ratio and figure out (let x be distance on map from Cleveland to Cincinnati):
![\frac{1}{50}=\frac{x}{40}\\50x=40\\x=\frac{40}{50}\\x=0.8](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B50%7D%3D%5Cfrac%7Bx%7D%7B40%7D%5C%5C50x%3D40%5C%5Cx%3D%5Cfrac%7B40%7D%7B50%7D%5C%5Cx%3D0.8)
Hene, 0.8 centimeters would be the distance in 2nd map
2.
A scale of 1:50 means 1 cm equal 50 cm
So, 0.8m would be
0.8 * 100 = 80 cm
Hence, 80 cm would be represented by 80/50 on the map, that is:
![\frac{80}{50}=1.6](https://tex.z-dn.net/?f=%5Cfrac%7B80%7D%7B50%7D%3D1.6)
That is 1.6 centimeters
Answer:
Step-by-step explanation:
Sound intensity corresponding to 80 dB: ![1\cdot 10^{-4}W/m^2](https://tex.z-dn.net/?f=1%5Ccdot%2010%5E%7B-4%7DW%2Fm%5E2)
Step-by-step explanation:
The decibel of a normal conversation is 60 dB, which corresponds to an intensity of
. (1)
The formula to use that relates the intensity of the sound in
to the sound level in decibel is
![\beta(dB)=10log_{10}(\frac{I}{I_0})](https://tex.z-dn.net/?f=%5Cbeta%28dB%29%3D10log_%7B10%7D%28%5Cfrac%7BI%7D%7BI_0%7D%29)
Where
is the sound level in decibel
is the intensity
We can found
by plugging in the numbers of (1):
![\frac{\beta(dB)}{10}=log_{10}(\frac{I}{I_0})\\\frac{I}{I_0}=10^{\frac{\beta(dB)}{10}}\\I_0 = \frac{I}{10^{\frac{\beta(dB)}{10}}}=\frac{1\cdot 10^{-6} W/m^2}{10^{\frac{60}{10}}}=1\cdot 10^{-12} W/m^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cbeta%28dB%29%7D%7B10%7D%3Dlog_%7B10%7D%28%5Cfrac%7BI%7D%7BI_0%7D%29%5C%5C%5Cfrac%7BI%7D%7BI_0%7D%3D10%5E%7B%5Cfrac%7B%5Cbeta%28dB%29%7D%7B10%7D%7D%5C%5CI_0%20%3D%20%5Cfrac%7BI%7D%7B10%5E%7B%5Cfrac%7B%5Cbeta%28dB%29%7D%7B10%7D%7D%7D%3D%5Cfrac%7B1%5Ccdot%2010%5E%7B-6%7D%20W%2Fm%5E2%7D%7B10%5E%7B%5Cfrac%7B60%7D%7B10%7D%7D%7D%3D1%5Ccdot%2010%5E%7B-12%7D%20W%2Fm%5E2)
Which corresponds to a sound level of 0 decibel.
Now we can find the intensity that corresponds to a sound level of
![\beta=80 dB](https://tex.z-dn.net/?f=%5Cbeta%3D80%20dB)
And from the equation we find:
![I=I_0 10^{\frac{\beta(dB)}{10}}=(1\cdot 10^{-12})10^{\frac{80}{10}}=1\cdot 10^{-4}W/m^2](https://tex.z-dn.net/?f=I%3DI_0%2010%5E%7B%5Cfrac%7B%5Cbeta%28dB%29%7D%7B10%7D%7D%3D%281%5Ccdot%2010%5E%7B-12%7D%2910%5E%7B%5Cfrac%7B80%7D%7B10%7D%7D%3D1%5Ccdot%2010%5E%7B-4%7DW%2Fm%5E2)
Learn more about sound waves:
brainly.com/question/4899681
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