The following times are given using metric prefixes on the base SI unit of time: the second. Rewrite them in scientific notation
without the prefix. For example, 47 Ts would be rewritten as 4.7×1013s. (a) 980 Ps; (b) 980 fs; (c) 17 ns; (d) 577μs.
2 answers:
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5.77 × Hz is the green photon's frequency .
The distance between similar points (adjacent crests) in adjacent cycles of a waveform signal that is propagated in space is known as the wavelength. A wave's wavelength is often measured in meters (m), centimeters (cm), or millimeters (mm) (mm). The relationship between frequency and wavelength is inverse.
<h3>Given:</h3>Wavelength of green light = 520 nm
f = c / λ
where, f = Frequency
c = Speed of light = 3 × m/s
λ = Wavelength of light
∴ f = c / λ
f =
= 5.77 × Hz
Therefore, 5.77 × Hz is the green photon's frequency .
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The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
=
= 23.04/10.3
= 2.23 m/s²
It continues to fly but now with some tangential acceleration
= 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
=
=
= 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
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Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So
k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be