Answer:Surface wave
Explanation:
Longitudinal wave is perpendicular to the wave motion and transverse wave is the same as the wave motion
Answer:
B
Explanation:
acceleration = change in speed / change in time
for 1, speed increases over time, so positive acceleration
for 3, speed decreases over time, so negative acceleration (or deceleration)
The average acceleration of the car as it accelerates from 15 m/s to 25 m/s will be 2.5 m/s².
<h3>What is Average acceleration?</h3>
Average acceleration is the average rate of change of velocity with respect to time. Mathematically -
a = Δv/Δt
Given that a car is traveling at 15 m/s in north direction and in 4 seconds it accelerates to 25 m/s in the north direction only. Therefore, we can write -
initial velocity [u] = 15 m/s
final velocity [v] = 25 m/s
time taken [Δt] = 4 s
The magnitude of the average acceleration can be calculated as follows-
a = Δv/Δt
Δv = v - u = 25 - 15
Δv = 10 m/s
Therefore -
a = 10/4
a = 2.5 m/s².
Therefore, the average acceleration of the car will be 2.5 m/s².
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Answer:
The boiling point of liquids always increases when pressure is applied on a liquid. This is because the molecules of a liquid will need more energy to turn into a gaseous state when pressure is applied on that substance.
(a) 0.448
The gravitational potential energy of a satellite in orbit is given by:
where
G is the gravitational constant
M is the Earth's mass
m is the satellite's mass
r is the distance of the satellite from the Earth's centre, which is sum of the Earth's radius (R) and the altitude of the satellite (h):
r = R + h
We can therefore write the ratio between the potentially energy of satellite B to that of satellite A as
and so, substituting:
We find
(b) 0.448
The kinetic energy of a satellite in orbit around the Earth is given by
So, the ratio between the two kinetic energies is
Which is exactly identical to the ratio of the potential energies. Therefore, this ratio is also equal to 0.448.
(c) B
The total energy of a satellite is given by the sum of the potential energy and the kinetic energy:
For satellite A, we have
For satellite B, we have
So, satellite B has the greater total energy (since the energy is negative).
(d) 
The difference between the energy of the two satellites is:
