Explanation:
This how you do it..
Calculate Watt-hours Per Day. Device Wattage (watts) x Hours Used Per Day = Watt-hours (Wh) per Day. ...
Convert Watt-Hours to Kilowatts. Device Usage (Wh) / 1000 (Wh/kWh) = Device Usage in kWh. ...
Find Your Usage Over a Month.
Answer:
Ф = 4.5176x10⁵ N . m² / C
Explanation:
In this case, we need to use two expressions in order to calculate the electric flux of the sphere.
First the Electric flux is calculated using this expression:
Ф = E * A (1)
Where:
E: Electric field
A: Area of the sphere
To get the electric field E, we use this expression:
E = K * q / r² (2)
If we replace (2) into (1) we have the following:
Ф = K * q * A / r² (3)
Finally, we need to know the expression to get the area of a sphere which is the following:
A = 4πr² (4)
Replacing into (3):}
Ф = K * Q * 4πr² / r² discarting r²:
Ф = K * Q * 4π (5)
Now, all we need to do is replace the given values and solve for the electric flux of the sphere:
Ф = 8.98755x10⁹ * 4x10⁻⁶ * 4 * π
<h2>
Ф = 4.5176x10⁵ N . m² / C</h2>
Hope this helps
Answer:
r=0.127
Explanation:
When connected in series
Current = I
When connected in parallel
Current = 10 I
We know that equivalent resistance
In series R = R₁+R₂
in parallel R= R₁R₂/(R₂+ R₁)
Given that voltage is constant (Vo)
V = I R
Vo = I (R₁+R₂) ------------1
Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2
From above equations
10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)
10 R₁R₂ = (R₁+R₂) (R₂+ R₁)
10 R₁R₂ = 2 R₁R₂ + R₁² + R₂²
8 R₁R₂ = R₁² + R₂²
Given that
r = R₁/R₂
Divides by R₂²
8R₁/R₂ = ( R₁/R₂)²+ 1
8 r = r ² + 1
r ² - 8 r+ 1 =0
r= 0.127 and r= 7.87
But given that R₂>R₁ It means that r<1 only.
So the answer is r=0.127
Imagine a skinny straw in the water, standing right over the hole. The WEIGHT of the water in that straw is the force on the tape. Now, the volume of water in the straw is (1 mm^2) times (20 cm). Once you have the volume, you can use the density and gravity to find the weight. And THAT's the force on the tape. If the tape can't hold that force, then it peels off and the water runs out through the hole. /// This is a pretty hard problem, because it involved mm^2, cm, and m^3. You have to be very very very careful with your units as you work through this one. If you've been struggling with it, I'm almost sure the problem is the units.
