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Assoli18 [71]
3 years ago
13

How does electromagnetic affect people in the world ?

Physics
1 answer:
tangare [24]3 years ago
5 0
That depends on the wavelength of the electromagnetic radiation.

-- If the waves are long, then we use them for radio, TV, and cellphones.

-- If the waves are shorter than that, then we use them for GPS in the car.

-- If the waves are shorter than that, then we use them to heat meatloaf
in the microwave oven.

-- If the waves are shorter than that, then they warm us and they
make our plants grow ... like the ones we eat.

-- If the waves are shorter than that, then our eyes use them to see with.

-- If the waves are shorter than that, then they tan our skin.

-- If the waves are shorter than that, then they can cause cancer on
our skin.

-- If the waves are shorter than that, then they can cause cancer and
other diseases in places inside our body.
You might be interested in
A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push
atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

3 0
3 years ago
An electric iron connected to a 110 V source draws 9 A of current. How much heat (in joules) does it generate in a minute?
meriva
Q = 110V x 9A x 60s = J
7 0
3 years ago
An electron at Earth's surface experiences a gravitational force of magnitude F=(9.11×10−31 kg)⋅(9.8 m/s2). Part A How far away
katrin [286]

Answer:

r = 5,085 m

Explanation:

The force exerted by on the surface of the Earth on an electron is its weight

          W = F = 9.11 10⁻³¹  9.8

          W = 8.9 10⁻³⁰ N

The electric force between an electron and a proton is given by Coulomb's Law

         Fe = k q₁ q₂ / r²

         Fe = - k q² / r²

They ask us that W = Fe

         W = k q² / r²

          r = √ k q² / W

Let's calculate

        r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰

        r = √ 25.86

        r = 5,085 m

Let's look for the relationship of this distance with the harmonic distance

        R / R_atomic = 5,085 / 10⁻¹⁰

        R / R_Atomic = 5 10¹⁰

We see that this distance is 10¹⁰ times the interatomic distance, so the gravitational attraction force is very small at atomic scale

8 0
3 years ago
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the
lys-0071 [83]

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

5 0
1 year ago
I need help with this Physics question!
just olya [345]
Mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
7 0
3 years ago
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