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Pie
3 years ago
5

Students in science class were asked to do an experiment with a can of soda. They placed an unopened can of soda on a digital sc

ale and recorded the initial mass as 340 g. They then opened the soda can and left it open for a day. The following day, the students took the mass of the soda can again and noticed that it was only 332g. They then poured some of the soda into a glass and observed that it was no longer fizzy.

Physics
1 answer:
ElenaW [278]3 years ago
5 0
Because the gas has left which once you open the soda can u can see the fizzy which is gas coming out of it
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An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate
riadik2000 [5.3K]

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

4 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
babymother [125]

Answer:

Explanation:

height of pole = 15 ft

height of man = 6 ft

Let the length of shadow is y .

According to the diagram

Let at any time the distance of man is x.

The two triangles are similar

\frac{y-x}{y}=\frac{6}{15}

15 y - 15 x = 6 y

9 y = 15 x

y=\frac{5}{3}x

Differentiate with respect to time.

\frac{dy}{dt}=\frac{5}{3}\frac{dx}{dt}

As given, dx/dt = 4 ft/s

\frac{dy}{dt}=\frac{5}{3}\times 4

\frac{dy}{dt}=\frac{20}{3} ft/s

6 0
4 years ago
A pulsar is a rapidly rotating neutron star. The Crab nebula pulsar in the constellation Taurus has a period of 33.5\times 10^{-
joja [24]

Answer:

5.25\cdot 10^{40} kg m^2/s

Explanation:

The angular momentum of the pulsar is given by:

L=m\omega r^2

where

m=2.8\cdot 10^{30} kg is the mass of the pulsar

r = 10.0 km = 1\cdot 10^4 m is the radius

\omega is the angular speed

Given the period of the pulsar, T=33.5\cdot 10^{-3} s, the angular speed is given by

\omega=\frac{2\pi}{T}=\frac{2 \pi}{33.5\cdot 10^{-3}s}=187.5 rad/s

And so, the angular momentum is

L=m\omega r^2=(2.8\cdot 10^{30}kg)(187.5 rad/s)(1\cdot 10^4 m)^2=5.25\cdot 10^{40} kg m^2/s

8 0
3 years ago
A pool ball is rolling at a velocity of 12 cm/s to the right when it is hit by another ball. It continues moving right at a velo
madam [21]

Answer:

B

Explanation:

Acceleration = rate of change in velocity

a = (21-12)/(0.45) = 20cm/s^2

6 0
3 years ago
Which term describes the time it takes for an object to complete one full cycle of motion on a spring?
Sav [38]

The term period (symbol: T) describes the time it takes for an object to complete one full cycle of motion on a spring.

The formula for time is: T  = 1 / f , where f is the frequency  , f= c / λ = wave speed c (m/s) / wavelength λ (m)..

The formula describes that as the frequency of a wave increases, the time period of the wave decreases.

4 0
3 years ago
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