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3 years ago

Suppose a mountain range is made up of 18 mountains, each mountain has

Chemistry

1 answer:

8_murik_8 [283]3 years ago

7 0

The answer is 1.98 x 10^10 leaves.

18 mountains x 8800 trees = 158400 total trees

158400 total trees x 125000 leaves = 19800000000 total leaves in entire mountain range

Sci not: 1.98 x 10^10 leaves

To do scientific notation, put the decimal place right after the first digit in the number and count how many places are behind the decimal. you'll write the number of places after the decimal after the ^ in the 10^.

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What is the study of acid-base chemistry called in the environment

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Answer:

An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

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3 years ago

A(n)__________<br>accepts electrons and becomes___________<br>

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3 years ago

What is the 3 types of matters

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Answer:

Solid, liquid, and gas

Explanation:

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3 years ago

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Helium is an odorless, colorless gas at room temperature. It is less dense than air. That's why helium balloons float. It is a n

Zolol [24]

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Non-flammable
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3 years ago

Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma

Elena-2011 [213]

Answer:

The yearly release of $CO_2$ into the atmosphere is $6.73\times 10^{10} kg$ .

Explanation:

$CaCO_3(s)\rightarrow CaO(s) + CO_2(g)$

Annual production of CaO = $8.6\times 10^{10} kg=8.6\times 10^{13} g$

Moles of CaO :

$\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles$

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with $1.53\times 10^{12} moles$ of CaO moles of carbon-dioxide moles produced will be:

$\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles$ of carbon-dioxide

Mass of $1.53\times 10^{12}$ moles of carbon-dioxide:

$1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg$

The yearly release of $CO_2$ into the atmosphere is $6.73\times 10^{10} kg$ .

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3 years ago