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lorasvet [3.4K]
3 years ago
11

Please help! Urgent!

Chemistry
1 answer:
sineoko [7]3 years ago
8 0

Answer:

?

Explanation:

? sorry

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A 5.0-L sample of sulfur hexafluoride (SF6) is stored at a temperature of 250.0 K and a pressure of 67.0 Pa. If the pressure is
Anna11 [10]

Answer:279.1 K

Explanation:

You'll be using Gay-Lussac's Law for this. P1/T1=P2/T2

I have a class for this, and one of the practice questions was formatted this way, so I used that format and substituted said numbers as needed

P1:67 Pa

P2:60 Pa

T1:250 K

T2:?

I really hope this helps!

4 0
3 years ago
Which of these statements best explains why pure water has a pH of 7? Pure water contains only H2O molecules, but pH is based on
Liula [17]

Answer:water self-ionize to form an equilibrium system that has [h30+]=1.0x10^-7 M

Explanation:

5 0
3 years ago
Read 2 more answers
(GIVING BRAINLIEST)<br><br> ....
erik [133]

Answer:

C

Explanation:

Because a planet is a celestial body distinguished from the fixed stars by having an apparent motion of its own (including the moon and sun), especially with reference to its supposed influence on people and events.

6 0
3 years ago
Read 2 more answers
Calculate the molar solubility of fe(oh)2 in pure water. (the value of ksp for fe(oh)2 is 4.87×10−17.)
rosijanka [135]
When we have this balanced equation for a reaction:
Fe(OH)2(s) ↔ Fe+2  + 2OH-

when Fe(OH)2 give 1 mole of Fe+2 & 2 mol of OH-
so we can assume [Fe+2] = X and [OH-] = 2 X
 when Ksp = [Fe+2][OH-]^2
and have Ksp = 4.87x10^-17 
[Fe+2]= X
[OH-] = 2X
so by substitution 
4.87x10^-17 = X*(2X)^2
∴X^3 = 4.8x10^-17 / 4
∴the molar solubility X = 2.3x10^-6 M
3 0
3 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
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