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vlabodo [156]
3 years ago
12

If the pOH of a nitric acid (HNO3) solution is measured as 11, what is the concentration of HNO3 solution? Choose one

Chemistry
1 answer:
miss Akunina [59]3 years ago
8 0
PH + pOH = 14

pH
= 14 - pOH
= 14 - 11
= 3

pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M
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Of the following transitions in the Bohr hydrogen atom, the ________ transition results in the emission of the lowest-energy pho
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N=6 ——> n=1
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In the reaction _____ H2+N2 --> 2 NH3,
ehidna [41]
A 3 should be placed in front of the H2 to balance it, since the 2 in front of NH3 says there are 6 H atoms. However on the other side, there are only 2. If we add the 3, 3 x 2 = 6. Then it is balanced.
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The process of manufacturing sulfuric acid begins with the burning of sulfur. What mass of sulfur would have to be burned in ord
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Answer:

about 327 g of sulfur

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Reaction equations.

2S + 2O2 = 2SO2

2SO2 + O2 = 2SO3

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3 years ago
The balanced chemical equation for the reaction of hydrogen and oxygen is shown below. 2H2 + O2 Right arrow. 2H2O The number of
bagirrra123 [75]

Answer:

Equal to 0.253 mol.

Explanation:

Hello,

In this case, since hydrogen and water are in a 2:2 molar relationship, the number of moles of hydrogen necessary to produce 0.253 mol of water will be also 0.253 mol as shown on the following stoichiometric factor:

n_{H_2}=0.253mol H_2O*\frac{2molH_2}{2molH_2O} =0.253mol H_2

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Copper(II) sulfide, CuS, is used in the development of aniline black dye in textile printing. What is the maximum mass of CuS wh
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Answer:

1.82 g   is the maximum mass of CuS.

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

<u>For CuCl_2 : </u>

Molarity = 0.500 M

Volume = 38.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 38.0×10⁻³ L

Thus, moles of CuCl_2 :

Moles=0.500 \times {38.0\times 10^{-3}}\ moles

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<u>For (NH_4)_2S : </u>

Molarity = 0.600 M

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The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 42.0×10⁻³ L

Thus, moles of (NH_4)_2S :

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According to the given reaction:

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0.019 mole of CuCl_2 reacts with 0.019 mole of (NH_4)_2S

Moles of (NH_4)_2S = 0.019 mole

Available moles of (NH_4)_2S = 0.0252 mole

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The formation of the product is governed by the limiting reagent. So,

1 mole of CuCl_2 gives 1 mole of CuS

0.019 mole of CuCl_2 gives 0.019 mole of CuS

Moles of CuS formed = 0.019 moles

Molar mass of CuS = 95.611 g/mol

Mass of CuS = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g

<u>1.82 g   is the maximum mass of CuS.</u>

5 0
4 years ago
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