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Svetradugi [14.3K]
4 years ago
15

_______ and _______ are located in the nucleus of the atom, while _______ exist in areas of probability around the nucleus.

Chemistry
1 answer:
fenix001 [56]4 years ago
5 0
Protons and neutrons exist within the neucleus, while electrons do not.
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When a system is at equilibrium________.
ikadub [295]

Answer:

The forward and the reverse processes are both spontaneous. (Ans. B)

Explanation:

When a system is at equilibrium state, then the rate of backwards, and forward, both reactions becomes equal. Which means the forward and the reverse processes are both spontaneous.

With the help of entropy change of the reaction, and Gibbs free energy we can determine the spontaneity of a reaction. If entropy changes is positive, and Gibbs free energy changes a negative, then the reaction will say to be spontaneous.

5 0
3 years ago
A regular solid measures 13.4 cm x 11.0 cm x 2.2cm. Calculate the volume of the solid.
AlekseyPX

Answer:

324.28 cm cubed

Explanation:

13.4 cm x 11.0cm x 2.2cm = 324.28 cm cubed

7 0
3 years ago
Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
postnew [5]

Answer:

1. Increased levels of fructose-2,6-bisphosphatase : Activate gluconeogenesis Inhibit glycolysis

2. Activation of fructose-2,6-bisphosphate (FBPase-2) : Activate glycolysis Inhibit gluconeogenesis

3. Increased glucagon levels : Activate gluconeogenesis Inhibit glycolysis

4. Activation of PFK-2 : Activate glycolysis Inhibit gluconeogenesis

5. Increased levels of CAMP : Activate gluconeogenesis Inhibit glycolysis

Explanation:

Glycolysis is the breakdown of glucose molecules in order to release energy in the form of ATP in response to the energy needs of the cells of an organism.

Gluconeogenesis is the process by which cells make glucose from other molecules for other metabolic needs of the cell other than energy production.

Glycolysis and gluconeogenesis are metabolically regulated in the cell by various enzymes and molecules.

The following shows the various regulatory methods and their effects on both processes:

1. The enzyme fructose-2,6-bisphosphatase functions in the regulation of both processes. It catalyzes the breakdown of the molecule fructose-2,6-bisphosphate which is an allosteric effector of two enzymes phosphofructokinasse-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase-1 which fuction in glycolysis and gluconeogenesis respectively.

Increased levels of fructose-2,6-bisphosphatase  activates gluconeogenesis and inhibits glycolysis by its breakdown of fructose-2,6-bisphosphate.

2. Fructose-2,6-bisphosphate increases the activity of PFK-1 and inhibits the the activity of FBPase-1. The effect is that glycolysis is activated while gluconeogenesis is inhibited.

3. Glucagon is a hormone that stimulates the synthesis of cAMP. It fuctions to activate gluconeogenesis and inhibit glycolysis.

4. Phosphosfructikinase-2, PFK-2 is an enzyme that catalyzes the formation of fructose-2,6-bisphosphate. Activation of PFK-2 results the activation of glycolysis and inhibition of gluconeogenesis.

5. Cyclic-AMP (cAMP) synthesis in response to glucagon release serves to activate a cAMP-dependent protein kinase which phosphorylates the bifunctional protein PFK-2/FBPase-2. This phosphorylation enhances the activity of FBPase-2 while inhibiting the activity of PFK-2, resulting in the  activation of gluconeogenesis and inhibition of glycolysis.

7 0
3 years ago
Why does galium melt
levacccp [35]

Answer:

Like most other metals, Gallium is solid at room temperature (or liquid if it is too hot in your room). But, if it is held [in hands] for long enough, it melts in your hands, and doesn't poison you like Mercury would. This is because of its unusually low melting point of (~29 degree Centigrade).

- It melts once it reaches its melting point.

:)

7 0
3 years ago
The average atomic mass of copper is 63.55 amu. If the only two isotopes of copper have masses of 62.94 amu and 64.93 amu, what
IgorLugansk [536]

Explanation:

Let relative ratio of one isotope (62.94 u) be X

Then, relative ratio of other isotope (64.93) will be (1 - X)

Now,

(62.94)x + (64.93)(1 - x) = 63.55

1.99x = 1.38

X = 0.69

<u>Relative Abundance</u> :

(62.94 u) isotope = 69 %

(64.93 u) isotope = 31 %

7 0
3 years ago
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