Find the greatest common factor of these three expressions. 28v4 , 12v5 , and 20v2

A cake mix calls for these ingredients. 2 cups of sugar 7 cups of flour 3 cups of milk 1 cup of oil Write the ratios of sugar to

Setler [38]

Answer:

Ratio of sugar and flour

2:7

Ratio of milk and oil

3:1

Step-by-step explanation:

Here in this question, we shall be writing ratios based on the given number of cups in the question.

We start with ratio of sugar to flour.

We have;2 cups of sugar and 7 cups of flour. Thus we have the ratio of sugar to flour as 2:7

Also we want the ratio of milk and oil

we have 3 cups of milk and 1 cup of oil

So the ratio of milk and oil is 3:1

5 0

3 years ago

Read 2 more answers

One True Love? A survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each pe

sertanlavr [38]

Answer:

99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

Step-by-step explanation:

We are given that a survey that asked whether people agree or disagree with the statement ‘‘There is only one true love for each person." has been conducted. The result is that 735 of the 2625 respondents agreed, 1812 disagreed, and 78 answered ‘‘don’t know."

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of people who disagree with the statement = $\frac{1812}{2625}$ = 0.69

n = sample of respondents = 2625

p = population proportion of people who disagree with statement

Here for constructing 99% confidence interval we have used One-sample z proportion statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.58 < N(0,1) < 2.58) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.58 & 2.58}

P(-2.58 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.58) = 0.99

P( $-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.58 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ , $0.69+2.58 \times {\sqrt{\frac{0.69(1-0.69)}{2625} } }$ ]

= [0.667 , 0.713]

Therefore, 99% confidence interval for the proportion of people who disagree with the statement is [0.667 , 0.713].

5 0

3 years ago

Can someone help me with number 4?

Rashid [163]

The US: 300m World: 9b Most accurate: B

300m•20=6b population

B is the most accurate

4 0

3 years ago

Factor completely. x2+3x−40 Enter your answer in the box.

Arlecino [84]

5x-40 if yo are trying to simplify it

7 0

3 years ago

find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29

AnnyKZ [126]

Answer:- The smaller integer is -5.

Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29 [distributive law]

⇒x+6x= -29-6 [subtract 6 on the both sides]

⇒7x= -35 [combining like terms ]

⇒x= -5 [dividing 7 on both sides]

Thus the smaller integer =x= -5

larger integer =x+1= -5+1= -4

3 0

3 years ago