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3 years ago

Does the suns light exhibit an emission spectrum?

1 answer:

algol133 years ago

7 0

Light is emitted in the visible spectrum to nearly all energies, so in the spectrum of the Sun you can see all colours. This is clearly not a continuous spectrum, but still represents visible radiation, divided into its component colours.

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What mass of TiCl4 must react with an excess of water to produce 50.0g of TiO2 if the reaction has a 78.9% yield

Kipish [7]

Answer:

\large \boxed{\text{150 g TiCl}_{4}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 189.68 79.87

TiCl₄ + 2H₂O ⟶ TiO₂ + 4HCl

m/g: 50.0

To solve this stoichiometry problem, you must

Convert the actual yield to the theoretical yield
Use the molar mass of TiO₂ to convert the theoretical yield of TiO₂ to moles of TiO₂
Use the molar ratio to convert moles of TiO₂ to moles of TiCl₄
Use the molar mass of TiCl₄ to convert moles of TiCl₄ to mass of TiCt₄

1. Theoretical yield of TiO₂

$\text{Theoretical yield} = \text{50.0 g actual} \times \dfrac{\text{100 g theoretical}}{\text{78.9 g actual}} = \text{63.37 g theoretical}$

2. Moles of TiO₂

$\text{Mass of TiO}_{2} = \text{63.37 g TiO}_{2} \times \dfrac{\text{1 mol TiO}_{2}}{\text{79.87 g TiO}_{2} } = \text{0.7934 mol TiO}_{2}$

3, Moles of TiCl₄

The molar ratio is 1 mol TiO₂:1 mol TiCl₄.

$\text{Moles of TiCl}_{4} = \text{0.7934 mol TiO}_{2} \times \dfrac{\text{1 mol TiCl}_{4}}{\text{1 mol TiO}_{2}} = \text{0.7934 mol TiCl}_{4}$

4. Mass of TiCl₄

$\text{Mass of TiCl}_{4} = \text{0.7934 mol TiCl}_{4} \times \dfrac{\text{189.98 g TiCl}_{4}}{\text{1 mol TiCl}_{4}} =\textbf{150 g TiCl}_{\mathbf{4}} \\\\\text{You must use $\large \boxed{\textbf{150 g TiCl}_{\mathbf{4}}}$}$

5 0

3 years ago

Uranus is much larger than Earth, with a surface area of 8.10 × 1015m2 with an atmosphere of low-density gases: 82.5% H2, 15.2%

sdas [7]

Answer:

mass of Uranus: 9.31x10^22 kg

Explanation:

As I stated in the comments, the question in this problem is to calculate the mass of Uranus, given it's conditions.

Now, we have the data of the atmosphere gases, but for calculations, this data is irrelevant.

To calculate the mass of Uranus, we can use the second law of Newton which is:

F = m * a (1)

In this case, the only Force exerting here would be the weight so:

F = m * g (2)

And the force of Uranus, can also be expressed in terms of pressure and Area so:

F = P * S (3)

Now, if we replace (3) in (2) we have:

P * S = m * g

Solving for m:

m = P * S / g (4)

We have all the data, therefore, let's replace it in the above expression to calculate the mass of Uranus:

m = 1x10^8 * 8.1x10^15 / 8.7

m = 9.31x10^22 kg

This is the mass of Uranus

8 0

4 years ago

Benzoic acid is in the process of being recrystallized. Your lab partner is in a hurry and after the impure benzoic acid is diss

bazaltina [42]

Answer:

Impurities will be trapped in the crystals of the benzoic acid crystallized in this manner.

Explanation:

After benzoic acid is dissolved in hot water, it should have been allowed to cool gradually before it is transferred into an ice bath.

This gradual cooling will aid the separation of impurities so that when the vessel is now submerged in an ice bath, only pure benzoic acid is recrystalized.

If the vessel is immediately submerged into an ice bath, impurities will be trapped in the crystals of the benzoic acid.

6 0

4 years ago

The solid has a mass of 180g. What is the density of the solid?

xxTIMURxx [149]

To find density we have to know the values of density and mass. Here mass is given which i 180g.
we know the formula to find the density is:
Density = Mass / volume
so the density will be 180 / volume = 180g per unit volume
if we know the volume, we can find exact value of density.

5 0

4 years ago

Ionization energy definition?

Gnom [1K]

Answer:

In physics and chemistry, ionization energy or ionisation energy, is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.

I hoped this helped :D

Explanation:

5 0

3 years ago