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topjm [15]
3 years ago
9

Based on the results of this lab, write a short paragraph that summarizes how to distinguish physical changes from chemical chan

ges.
Chemistry
2 answers:
Naddika [18.5K]3 years ago
4 0
A physical change is reversible, a substance change isn't. A physical change is an adjustment in which no new substance is shaped; a synthetic change brings about the arrangement of at least one new substances
kozerog [31]3 years ago
4 0

Physical changes occur when the properties of a substance are retained and/or the materials can be recovered after the change. Chemical changes involve the formation of a new substance. Formation of a gas, solid, light, or heat are possible evidence of chemical change.

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Explain why fluorine and chlorine are in the same group of the periodic table.
Ivenika [448]

Answer:

They both have 7 electrons in their outer shell

8 0
2 years ago
An increase in blood co2 levels leads to __________.
tatiyna

Answer:

Respiratory Acidosis

Explanation:

4 0
3 years ago
How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
At a certain temperature, the solubility of strontium arsenate, sr3(aso4)2, is 0.0560 g/l. what is the ksp of this salt at this
REY [17]
The solution for this problem is:
Get into moles first. .0560 grams over 540.8 grams per mole = 1.04 x l0^-4 moles 
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq) 
Ksp = (Sr++)^3(As04^-3)^2 
(Sr++) = 3 X 1.04 x l0^-4= 3.11 x l0^-4 
(As04^-3) = 2 x 1.04 x l0^-4= 2.07 x l0^-4 
Ksp = (1.04 x l0^-4)^3 (2.07 x l0^-4)^2 which equals 4.82 x 10^-20
5 0
3 years ago
PLEASE HELP MEI BEG YOU!!!!
Fittoniya [83]
The second one is, "<span>Be careful to present only objective facts"</span>
7 0
3 years ago
Read 2 more answers
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