The final temperature = 36 °C
<h3>Further explanation</h3>
The balanced combustion reaction for C₆H₆
2C₆H₆(l)+15O₂(g)⇒ 12CO₂(g)+6H₂O(l) +6542 kJ
MW C₆H₆ : 78.11 g/mol
mol C₆H₆ :
Heat released for 2 mol C₆H₆ =6542 kJ, so for 1 mol
Heat transferred to water :
Q=m.c.ΔT
Answer:
B- The polarity of the molecules and hydrogen bonding between molecules.
Explanation:
Hope this helps:)
For a gas containing 80% CH4 and 20% He is sent through a quart diffusion tube, the composition is mathematically given as
%He=12.5%
%CH4=87.5%
<h3>What is the
composition of the waste gas if 100 kg moles of gas are processed per minute?</h3>
Generally, the equation for the Material balance is mathematically given as
F=R+W
Therefore
100=0.20*1000+W
W=80kmol/min
In conclusion, waste gas compose
2.0/100*100=50/100*20+%*80
Hence
%He=12.5%
%CH4=87.5%
Read more about Chemical reaction
brainly.com/question/16416932
If you have 58.93g of Co it means that you only have 1 mol (use a periodic table to find the answer, if you had more find it by proportion, it's easier).
There's 6.022 x 10^23 atoms per mol so you have 6.022 x 10^23 atoms of Co.
(once again if you had more mol, you could find the answer by proportions).
Oxygen carbon and hydrogen
