Answer:
Limiting - Na Excess - Cl2
Explanation:
Erm, I think when they are little. When they are just born.
Answer:
2.42L
Explanation:
Given parameters:
V₁ = 1.8L
T₁ = 293K
P₁ = 101.3kPa
P₂ = 67.6kPa
T₂ = 263K
Unknown:
V₂ = ?
Solution:
To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;
All the units are in the appropriate form. We just substitute and solve for the unknown;
101.3 x 1.8 / 293 = 67.6 x V₂ / 263
V₂ = 2.42L
The resistance of the heating element is 21.61 Ω
Given
The power dissipated = 1500 W
Voltage = 180 V
We know that
Power = Voltage * Current
⇒ Power / Voltage = Current
⇒ 1500 W/180 V = Current
⇒ 8.33 A = Current
In order to calculate the resistance of the heating element. We Have to apply the formula
Power = (Current)^2 * Resistance
⇒ Resistance = Power / (Current)^2
⇒ Resistance = 1500 W/ (8.33) ^2
⇒ Resistance = 21.61 Ω
Hence the resistance of the heating element is 21.61 Ω
Learn more about resistance here: -
“ brainly.com/question/17330679 “
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In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.
So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.
Learn more about number of moles here:
brainly.com/question/3935424
