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Mariulka [41]
3 years ago
9

(ch3)2choh(g)⇌ (ch3)2co(g)+h2(g) δh∘ = +57.3kj what is delta s

Chemistry
1 answer:
ryzh [129]3 years ago
6 0
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determine the volume of your 0.25 m stock solution that is needed to make 200 ml of 0.010 m nacl. show all calculations
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The volume of your 0.25 m stock solution that is needed to make 200 ml of 0.010 m NaCl is <u>0.008 L</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Calculation:-

C₁ =  0.25 M

V₁ = ?

C₂ = 0.010 M

V₂ = 200 ml = 0.2 L

V₁ = C₂V₂/C₁

    = 0.010 ×  0.2 /  0.25

   =<u> 0.008 L</u>

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

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5 0
9 months ago
What is the mass of 1.7 × 1023 atoms of zinc (Zn)?
Rudiy27

Number of moles is defined as the ratio of given mass in g to the molar mass.

The mathematical formula is:

Number of moles = \frac{given mass in g}{molar mass}   (1)

Number of zinc atoms is equal to 1.7\times10^{23}, by Avogadro number, number of moles can be calculated.

As, 1 mol=6.022\times10^{23} atoms, hence,

1.7\times10^{23}\times\frac{1 mol}{6.022\times10^{23} }

= 0.2822 mol

Now, from formula (1), calculate mass in g (molar mass of zinc = 65.4 g/mol)

0.2822 mol = \frac{mass in g}{65.4 g/mol}

mass in g  = {0.2822 mol \times 65.4 g/mol

= 18.45588 g

Thus, by rounding off the above number, it will come near about 19 g approximately.

Hence, option (C) is the correct answer.



 



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