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worty [1.4K]
3 years ago
11

Which measurement contains three significant figures?

Chemistry
2 answers:
maxonik [38]3 years ago
8 0
The answer is C because you don’t have to worry about the number in front of the decimal unless it is something greater than zero. A- Doesn’t have there sig figs. B- The zero after the 5 doesn’t change it. D- The three at the end doesn’t matter because it does not round it up.
nadezda [96]3 years ago
3 0
A i think a is right 0.05
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Consider the following intermediate chemical equations. 2 equations. First: upper C (s) plus one half upper O subscript 2 (g) ri
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The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

The chemical equations are the representation of the chemical formula involved in the equation as the reactant and the formed product.

<h3>What will be the form of oxygen?</h3>

The given chemical equations are:

  1. \rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO\;(g)
  2. \rm CO\;(g)+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO_2\;(g)

The final chemical equation formed for the formation of Carbon dioxide is the sum of the two equations.

The final equation is achieved by substituting equation 1 in equation 2.

\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\;+\;\dfrac{1}{2}\;O_2\;(g)\;\rightarrow\;CO_2\;(g)\\\\   C\;(s)\;+\;O_2\;(g)\;\rightarrow\;CO_2\;(g)

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

Learn more about the final equation, here:

brainly.com/question/2264209

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A sample from solution a and solution b were each tested with blue colored glucose indicator solution before the solutions were
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With the given problem you gave here, I can't answer the question because I need more details. Luckily, I found a similar problem that's provided with a diagram and a table shown in the attached picture.

This test is called the Benedict's test which is used as test for presence of sugars. If the solution contains sugar, like glucose, the solution would turn from blue to red. If not, it would stay blue. <em>Therefore, the correct results would be that in row 3.</em>

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