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mixas84 [53]
4 years ago
9

Explain the result when aluminum is placed between the liquid and the wick

Chemistry
1 answer:
sammy [17]4 years ago
8 0
<span>The wick merely transports some of the liquid up to where vaporizes.It is not part of reaction but it does affect the reaction rate greatly,so it is a sort of catalyst in that time.if you wrap the wick in the aluminum it will block the transport the wax and it will wither go out less or brightly</span>
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Which of the following types of bonds will have the highest electrical conductivity?
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Please help fast!!! What does the weight of an object depend on?
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What is the molecular mass for a non-electrolyte if 35.0 g of it is dissolved in 45.0 grams of water and the solutions boiling p
adelina 88 [10]

The boiling point of water increases as the amount of impurities dissolved in it increases. For our purposes, we will consider the non-electrolyte to be the dissolved impurity. The change in the boiling point can be calculated using the equation:

\Delta T_b = i \times K_b \times m

where \Delta T_b is the change in boiling point, i is the van ‘t Hoff factor (whose value denotes the number of particles each formula unit of the dissolved substance dissociates into in water), K_b is the boiling point elevation constant, and m is the molality (moles of solute/kilogram of solvent) of the solution.

Right off the bat, since we're dealing with a non-electrolyte, the dissolved substance can be assumed not to dissociate in water. So, our van ‘t Hoff factor, i, would be 1 (by contrast, the i for an ionic compound like NaCl would be 2 since, in water, NaCl would dissociate into two particles: one Na⁺ ion and one Cl⁻ ion). We're also given our K_b, which is 0.51 °C/<em>m</em>.

Assuming the normal boiling point of pure water to be 100 °C (a defined value for sig fig purposes), the change in boiling point from having dissolved 35.0 g of the non-electrolyte can be obtained by subtracting 100 °C from the final—elevated—boiling point of 101.25 °C:

\Delta T_b = 101.25\text{ }^o\text{C} - 100\text{ }^o\text{C} = 1.25\text{ }^o\text{C}

Now, recall what we're asked to determine: the molecular mass of the dissolved substance. There is one unknown left in the equation: the molality of the solution. Let's first solve for that:

m = \frac{\Delta T_b}{K_b} = \frac{1.25^\text{ o}\text{C}}{0.51^\text{ o}\text{C}/m} \\ m = 2.45 \text{ mol solute/kg water}.

Notice that we didn't include the <em>i </em>since its value is 1.

Now, what would happen if we multiplied our molality by the mass of water we've been given? We would be left with the moles of solute. And what are we asked to find? The molecular mass, or the mass per mole. We can accomplish this in two steps. Remember to convert your mass of water to kilograms:

2.45 \text{ mol solute/kg water} \times 0.045 \text{ kg water} = 0.110 \text{ mol solute.}

And, finally, we divide the mass of our solute by the number of moles of solute:

\frac{35.0 \text{ g solute}}{0.110 \text{ mol solute}} = 317.5 \text{ g/mol}

Our answer to two significant figures (which is the number of sig figs to which our K_b is given) would be 320 g/mol.

5 0
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Explanation:

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As a result, its temperature will be minimum as its molecules have least kinetic energy.

It is known that kinetic energy of a substance is directly proportional to temperature.

As,            K.E = \frac{3}{2}kT

where            K.E = kinetic energy

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                       k = boltzmann constant

When solid changes into liquid state then it means molecules of a substance has gained kinetic energy due to which there occurs more collisions between the molecules.

Hence, temperature of substance also increases.

Whereas when liquid state of a substance changes intro vapor state then it means that more kinetic energy has gained by the molecules due to which there will be much more collisions between the molecules.

Hence, temperature will be maximum in vapor state.

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