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Doss [256]
3 years ago
6

8x^2+23=823 whats going to be the answer I got 0 am I right?

Mathematics
1 answer:
Naily [24]3 years ago
5 0
1) No; you are incorrect.  "0" is NOT a solution.

Plug in "0" for "x" ;

8*0² + 23 =? 823? ; 

8*0  + 23 =? 823? ;

  0 + 23 = ? 823 ? ;  No! ;  "0 + 23 = 23 " ; NOT "823" .
_________________________________________________
2)  The answers:  x = 10, -10 ; or, write as:  x = ± 10 .
_________________________________________________

To solve:

GIven:  8x² + 23 = 823 ; 

Subtract "23" from EACH SIDE of the equation:
_____________________________________________
           8x² + 23 - 23 = 823 - 23 ; 
to get:  
           8x²  = 800 ; 

Now, divide EACH SIDE of the equation by "8" ; 

          8x² / 8 = 800 / 8 ;

to get:  x² = 100 ; 

        Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ; 

          √(x²) = √(100) ;

             x  = <span>± 10 .

The answers:  x = 10, -10 ; or, write as:  x = </span><span>± 10 .
_____________________________________________________</span>
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Step-by-step explanation:

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Now here, you have two of the same variables (x, y, etc). So, what you do is look at the last number that has the same variables, which is 4, and look at what the problem you will be solving, which is addition. So, very simply, you add then together!

12× + 4× = 16×

As you can see I kept the same variable. This is because, well, it is the same! Simply, just substitute in the 16× with the 8y. Now here is the tricky part, for some people. Do you see that there is a negative sign in front of the 8 (-)? Well! You have to substitute that in with the expression. No adding this or anything, just simply slide it next to the 16× because, we can not add nor subtract it with the 8y just because it has a different variable.

Your example answer would be: 16× - 8y

Hope this helps!

P.S. if you think this helped you at all, Brainliest me if ya want to. Have a great day!

5 0
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ivolga24 [154]

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