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Studentka2010 [4]

3 years ago

15

A plane flying horizontally at a speed of 50m/s and at an elevation of 160m drops a package, and 2.0 s later it drops a second p

ackage. How far apart will the two packages land on the ground if air resistance is negligible?

1 answer:

babymother [125]3 years ago

8 0

Answer: idkExplanation:

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An instrument that measures and detects vibrations in earth is known as a _______.

FinnZ [79.3K]

A boom box, stereo set.

5 0

3 years ago

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How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air

Tcecarenko [31]

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

y = -(1/2)(9.8 m/s^2)(3 s)^2 + (40 m/s)(3 s)

= -44.1 m + 120 m

= 75.9

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2 years ago

The angular velocity of a flywheel obeys the equa tion w(1) A Br2, where t is in seconds and A and B are con stants having numer

makkiz [27]

Answer:

$A \to rad/s$

$B \to rad/s^3$

Explanation:

$\omega_z(t)=A + Bt^2$

Required

The units of A and B

From the question, we understand that:

$\omega_z(t) \to rad/s$

This implies that each of $A$ and $Bt^2$ will have the same unit as $\omega_z(t)$

So, we have:

$A \to rad/s$

$Bt^2 \to rad/s$

The unit of t is (s); So, the expression becomes

$B * s^2 \to rad/s$

Divide both sides by $s^2$

$B \to \frac{rad/s}{s^2}$

$B \to rad/s^3$

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2 years ago

If a resource is non renewable, it ____

Karolina [17]

it cannot be reuse and replaced for long period of time.hope it helps u

4 0

2 years ago

A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is

dsp73

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

<em>Mass of the pitcher, m₁ = 50 kg</em>
<em>Mass of the baseball, m₂ = 0.15 kg</em>
<em>Velocity of the ball, u₂ = 35 m/s</em>

<em />

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

$u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s$

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/13589460

4 0

1 year ago