For circular motion we know that
<span>F=ma=v^2/r </span>
<span>Therefore: </span>
<span>v = sqrt (rma) </span>
<span>Also, for cicular motion: </span>
<span>rev/min. = 60v/(2r*pi) </span>
<span>So your equation is: </span>
<span>rev./min = 60sqrt(rma)/(2pi*r) </span>
<span>For the mass (m) we can just use 1 kg.
</span>
rev./min = 60sqrt(730*1*9.8)/(2pi*730) =60sqrt(7154)/(4584.4)
rev./min = 60sqrt(7154)/(4584.4) =1.11 rev/min
<span>
the answer is </span>1.11 rev/min<span>
</span>
Answer:
A boat can travel 2.30 m/s in still water. (a) If the boat points its prow directly across a stream whose current is. ... (a) What is the velocity (magnitude and direction) of the boat relative to the shore? ... The boat's velocity with respect to the shore, , is the sum of its velocity with respect to the water
Explanation:
Answer:
Starts on Saturday, June 1
and ends on
Saturday, November 30
Explanation:
It is diffraction
Explanation:
The opening is the aperture
