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sashaice [31]
3 years ago
11

A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

Physics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

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Law of conservation of momentum states that when two objects collide with each other , the sum of their linear momentum always remains same or we can say conserved and is not effected by any action, reaction only in case is no external unbalanced force is applied on the bodies.
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= initial velocity of ball A
u
B
​
= initial velocity of ball B
v
A
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= Velocity after the collision of ball A
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B
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= Velocity after the collision of ball B
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Change in the momentum of A= momentum of A after the collision - the momentum of A before the collision
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v
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Rate of change of momentum A= Change in momentum of A/ time taken
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t
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v
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​

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−m
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u
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​
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​

Force exerted by A on B (F
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​
v
B
​
−m
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u
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​
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t
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v
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​

m
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