Answer:
v = 3×10^8 m/s
s= 384,400 km= 3.84×10^8 m/s
t = ?
v = s/t = 2s/t
t = 2s/v
t = (2×3.84×10^8) ÷ 3×10^8
t = 2.56 seconds
Explanation:
Earth's moon is the brightest object in our
night sky and the closest celestial body. Its
presence and proximity play a huge role in
making life possible here on Earth. The moon's gravitational pull stabilizes Earth's wobble on its axis, leading to a stable climate.
The moon's orbit around Earth is elliptical. At perigee — its closest approach — the moon comes as close as 225,623 miles (363,104 kilometers). At apogee — the farthest away it gets — the moon is 252,088 miles (405,696
km) from Earth. On average, the distance fromEarth to the moon is about 238,855 miles (384,400 km). According to NASA , "That means 30 Earth-sized planets could fit in between Earth and the moon."
pitch goes up on approach ... Doppler effect
<em>Answer:</em>
<em>When </em><em>a </em><em>body </em><em>is </em><em>moving </em><em>on </em><em>a </em><em>circle </em><em>it </em><em>is </em><em>accelerating </em><em>because </em><em>centripetal </em><em>acceleration</em><em> </em><em>is </em><em>always </em><em>acting </em><em>on </em><em>it </em><em>towards </em><em>the </em><em>center.</em>
<em>Please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em>.</em><em>.</em><em>.</em>
<em>From </em><em>the </em><em>above </em><em>diagram,</em><em>we </em><em>can </em><em>say </em><em>the </em><em>acceleration</em><em> </em><em>is </em><em>always </em><em>acting </em><em>on </em><em>the </em><em>body </em><em>when </em><em>it </em><em>moves </em><em>in </em><em>a </em><em>circle.</em>
<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
Answer:
Its momentum is multiplied by a factor of 1.25
Explanation:
First, we <u>calculate the initial velocity of the object</u>:
- 59.177 J = 0.5 * 3.4 kg * v₁²
With that velocity we can <u>calculate the initial momentum of the object</u>:
Then we <u>calculate the velocity of the object once its kinetic energy has increased</u>:
- (59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²
And <u>calculate the second momentum of the object</u>:
Finally we <u>calculate the factor</u>: