A 2.00 kg ball is thrown upward at some unknown angle from the top of a 20.0 m high building. If the initial magnitude of the ve
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<span>The height (h) of a triangle is 4 in. greater than twice its base (x): h = 2x + 4
</span>The area of the triangle is no more than 168 in.2: A ≤ 168 in²
The area of the triangle is A = x*h/2
Hence x*h/2 ≤ 168 in²
Substitute h in the formula for the area:
h = 2x + 4 = 2(x + 2)
x*h/2 ≤ 168 in²
x * 2(x + 2)/2 ≤ 168
x * (x + 2) ≤ 168
x² + 2x ≤ 168
x² + 2x - 168 ≤ 0
Using the formula for quadratic equation: