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fomenos
3 years ago
9

20 Accelerated motion is represented by a line on a nonlinear distance time graph.

Physics
1 answer:
Varvara68 [4.7K]3 years ago
3 0

Curved line

Explanation:

Acceleration of motion is represented by a curved line on a non-linear distance-time graph.

The acceleration of a non-linear motion is depicted using a parabola which is a curve. This implies that the velocity is constantly changing and the distance covered by the body is also changing with equal amount of time.

  • A plot of this will give a parabola. This can be further established using one of the equations of motion below:

    x = u + \frac{1}{2}at ²

This is a quadratic function where:

x is the distance

u is the initial velocity

t is the time

a is acceleration

A quadratic function gives a curved line which is a parabola.

Learn more:

Acceleration brainly.com/question/10932946

#learnwithBrainly

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a projectile is fired from the ground with an initial horizontal velocity of 8 meters per second. its initial vertical velocityi
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a projectile is fired from the ground with an initial horizontal velocity of 8 meters per second. its initial vertical velocityis 6 meters per second. whats is the "total/resultant" velocity of the projectile at its peak?


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Answer:

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Explanation:

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Identify two changes in your world that might occur if funding for scientific research were cut drastically
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Answer:

Little to no scientific advancement

More wide spread diseases

Explanation:

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3 years ago
A circular conducting loop with a radius of 0.10 m and a small gap filled with a 10.0 ȍresistor is oriented in the xy-plane. If
lidiya [134]

Answer:

The magnitude of the current is 5.45 mA.

Explanation:

Given that,

Resistance = 10.0 ohm

Radius = 0.10 m

Magnetic field = 1.0 T

Angle = 30°

Increase magnetic field = 7.0 T

Time t = 3.0 s

Number of turns = 1

We need to calculate the initial flux

Using formula of flux

\phi=NB_{1}A\cos\theta

Put the value into the formula

\phi=1\times1.0\times\pi\times(0.10)^2\times\cos30^{\circ}

\phi=1\times1.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.027\ wb

We need to calculate the final flux

\phi=1\times7.0\times\pi\times(0.10)^2\times\dfrac{\sqrt{3}}{2}

\phi=0.1904\ wb

We need to calculate the induced emf

Using formula of emf

\epsilon=\dfrac{\phi_{f}-\phi_{i}}{t}

Put the value into the formula

\epsilon=\dfrac{0.1904-0.027}{3.0}

\epsilon=0.0545\ V

We need to calculate the current

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value into the formula

I=\dfrac{0.0545}{10.0}

I=5.45\ mA

Hence, The magnitude of the current is 5.45 mA.

4 0
3 years ago
A runner is jogging in a straight line at a
murzikaleks [220]

Explanation:

The runner was 8.6km away from the finish line when the bird starts flying.

Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.

In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.

Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.

Hence, they will meet in 6.44/18.0 = 0.36 hours.

Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.

4 0
3 years ago
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