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fomenos
2 years ago
9

20 Accelerated motion is represented by a line on a nonlinear distance time graph.

Physics
1 answer:
Varvara68 [4.7K]2 years ago
3 0

Curved line

Explanation:

Acceleration of motion is represented by a curved line on a non-linear distance-time graph.

The acceleration of a non-linear motion is depicted using a parabola which is a curve. This implies that the velocity is constantly changing and the distance covered by the body is also changing with equal amount of time.

  • A plot of this will give a parabola. This can be further established using one of the equations of motion below:

    x = u + \frac{1}{2}at ²

This is a quadratic function where:

x is the distance

u is the initial velocity

t is the time

a is acceleration

A quadratic function gives a curved line which is a parabola.

Learn more:

Acceleration brainly.com/question/10932946

#learnwithBrainly

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A group of protons and neutrons that are surrounded by electrons  I think that's the answer...

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Answer:

Explanation:

F = ma

<u>Assuming</u> the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

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2 years ago
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball initially moving in th
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Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

<h3>What is conservation of momentum?</h3>

Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,

m_1u_1 + m_2u_2 = (m_1+m_2)v

Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,

v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}

A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,

v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}

Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,

v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s

Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.

Learn more about the conservation of momentum here;

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4 0
1 year ago
a stomp rocket takes 1.5 seconds to reach its maximum height what was the initial velocity and what was the maximum height ?
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3 years ago
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A particle moves along a straight path through a displacement d = 2.5i + cj while a force F = 8.5i + -8.5j acts on it. The displ
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Answer:

Explanation:

Work is defined as the scalar product of force and distance

W=F•d

Given that

F = 8.5i + -8.5j. +×-=-

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d = 2.5i + cj

If the work in the practice is zero, then W=0

therefore,

W=F•ds

0=F•ds

0=(8.5i -8.5j)•(2.5i + cj)

Note that

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i.j=j.i=k.i=i.k=j.k=k.j=0

So applying this

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8.5c=21.25

c=21.25/8.5

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