Answer:
the work done by the lawnmower is 236.14 J.
Explanation:
Given;
power exerted by the lawnmower engine, P = 19 hp
time in which the power was exerted, t = 1 minute = 60 s.
1 hp = 745.7 watts
The work done by the lawnmower is calculated as follows;

Therefore, the work done by the lawnmower is 236.14 J.
It depends, because worm holes are theoretical construed of space and time. It hasn’t been proven to exist but mathematically it hasn’t been spotted but we also haven’t been very far in our universe.
So to cut the story short, it is not a proven phenomenon only theoretical.
Answer:
Rectilinear propagation describes the tendency of electromagnetic waves to travel in a straight line. Light does not deviate when travelling through a homogeneous medium, which has the same refractive index throughout; otherwise, light suffers refraction.
Answer:
Aerobic Fitness, Muscular Fitness, Flexibility, and Stability and Balance.
Explanation:
Answer:
voltage measured by the voltmeter = (E × RV)/(r + RV)
Explanation:
The circuit diagram for this description is presented in the attached image.
The internal resistance of an emf source is modelled to be in series with the source.
Therefore, the end product is a circuit with the battery in series connection with the internal resistance and resistance of the volunteer. The voltage picked up by the volunteer is the voltage across resistor RV.
Total resistance in the circuit = (r + RV) ohms (since both resistors are in parallel)
Current produced by the emf source = E/(Total resistance) = E/(r + RV)
The voltage across resistor RV = current flowing through this resistor × its resistance.
Since all the circuit elements are in series with each other, same current, E/(r + RV) flows through them all
Voltage across RV = voltage measured by the voltmeter = [E/(r + RV)] × RV = (E × RV)/(r + RV) = (E.RV)/(r + RV)