Answer:
The magnitude of F when t=4 s=146.64 N
Explanation:
We are given that
Mass of crate,m=6.00 kg
Height of crate above its initial position is given by

We have to find the magnitude of F when t=4.00 s
Differentiate w.r.t t
![\frac{dy}{dt]=2.8+3(0.61)t^2](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%5D%3D2.8%2B3%280.61%29t%5E2)



Now, magnitude of force

Hence, the magnitude of F when t=4 s=146.64 N
party and being happy..........
Answer:
v_oy = 16.33 m/s
Explanation:
To find the vertical velocity of the tiger, you use the information about the horizontal velocity and maximum horizontal distance traveled.
You use the following formula for the range of the trajectory:
( 1 )
v_ox: horizontal initial velocity = 4.5m/s
v_oy: vertical initial velocity = ?
g: gravitational acceleration = 9.8m/s^2
x_max: range of the trajectory = 15 m
You do v_oy the subject of the formula ( 1 ) and you replace the values of the other parameters in order to calculate v_oy:

hence, the initial vertical velocity of the tiger is 16.33m/s
The answers are 3.3kWh, 1.2kWh, and 120kWh.
Multiply the amount of kW used per hour by the amount of time it was powered and you receive your answer.