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saw5 [17]
4 years ago
8

Imagine a Rip-van-Winkle type who lives in the mountains. Just before going to sleep he yells "WAKE UP" and the sound echoes off

the nearest mountain and returns 8 hours later.
How far away is that mountain? The speed of sound is __ m/s.
Physics
1 answer:
stiv31 [10]4 years ago
6 0

Answer:

4939200 m

Explanation:

v = Velocity of sound in air = 343 m/s (general value)

For the echo to reach Rip van Winkle it must cover the distance to the mountain twice. So, time taken for the sound traveling to the mountain once

t=\dfrac{8}{2}=4\ hr

Distance is given by

s=vt\\\Rightarrow s=343\times 4\times 60\times 60\\\Rightarrow s=4939200\ m=4939.2\ km

The distance to the mountain is 4939200 m

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8 0
4 years ago
What is the equivalent resistance of the circuit?
podryga [215]

Answer:

Option D. 5.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistance 1 (R₁) = 10 Ω

Resistance 2 (R₂) = 20 Ω

Resistance 3 (R₃) = 30 Ω

Voltage (V) = 120 V

Equivalent resistance (R) =?

The equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/20 + 1/30

Find the least common multiple (lcm) of 10, 20 and 30. The result is 60

Divide 60 by each of the denominators and multiply by their numerators respectively. We have:

1/R = (6 + 3 + 2)/60

1/R = 11/60

Invert

R = 60/11

R = 5.45 Ω

Thus, the equivalent resistance in the circuit is 5.45 Ω

8 0
3 years ago
A ship maneuvers to within 2.50 x 10^3 m of an islands 1.80 x 10^3 m high mountain peak and fires a projectile at an enemy ship
Neporo4naja [7]

Answer:

Explanation:

Distance between ship and enemy ship

= 500 + 610

= 3110 m

Range of projectile

R = u² sin2θ / g

= (250x 250 sin 150) / 9.8

= 3188m

The projectile falls within a distance of 3188 - 3110 = 78 m from enemy ship

Height of mountain = 1800 m

We shall find the height of projectile when its horizontal displacement is 2500m

x = 2500 , y = ?

u = 2500 ,

y = x / cos θ - .5 g x² /u²cos² θ

\frac{2500}{.2588} - \frac{.5 \times9.8\times2500\times2500}{250\times250\times.2588}

9660 - 7315 m

= 2345 m

It is within 545 m from mountain peak .

8 0
3 years ago
A superball with a mass m = 61.6 g is dropped from a height h = [02]____________________ m. It hits the floor and then rebounds
aleksklad [387]

<em>There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem</em>

Answer:

(a) \Delta P=1.67 \ kg.m/s

(b) \Delta P=0.86\ m/s

Explanation:

<u>Change of Momentum</u>

The momentum of a given particle of mass m traveling at a speed v is given by

P=m.v

When this particle changes its speed to a value v', the new momentum is

P'=m.v'

The change of momentum is

\Delta P=m.v'-m.v

\Delta P=m.(v'-v)

Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.

(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:

U=m.g.h=0.0616\cdot 9.8\cdot 10 =6.0368\ J

This potential energy is transformed into kinetic energy just before the collision occurs, thus

\displaystyle \frac{1}{2}mv^2=6.0368

Solving for v

\displaystyle v=\sqrt{\frac{6.0368\cdot 2}{0.0616}}

v=-14\ m/s

This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is

h'=88.5\% (10)=8.85\ m

The potential energy reached by the ball at its rebound is

U'=m.g.h'=0.0616\cdot 9.8\cdot 8.85 =5.342568\ J

Thus the speed after the collision is

\displaystyle v'=\sqrt{\frac{5.342568\cdot 2}{0.0616}}

v'=13.17\ m/s

The change of momentum is

\Delta P=0.0616\cdot (13.17+14)

\Delta P=1.67 \ kg.m/s

(b) If the putty sticks to the floor, then v'=0

\Delta P=0.0616\cdot (0+14)

\Delta P=0.86\ m/s

3 0
4 years ago
A jeweler is determining the optical properties of an unknown blue gemstone. She uses an angle of incidence of 62°, and measures
Juliette [100K]

Answer:

n = 1.76

Explanation:

According to the rule of ( n1 sin theta1 = n2 sin theta2 )

we know both angles so we insert them to the law and apply n1 = 1

so 1/2 = n2 sin 62 and we get the final answer

3 0
4 years ago
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