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Trava [24]
3 years ago
15

What affect does an increase in the angle of incidence have upon the angle of reflection?

Physics
1 answer:
valentina_108 [34]3 years ago
6 0
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Calculate the work against gravity required to build the right circular cone of height 4 m and base of radius 1.2 m out of a lig
Nana76 [90]

Answer:

Work done = 35467.278 J

Explanation:

Given:

Height of the cone = 4m

radius (r) of the cone = 1.2m

Density of the cone = 600kg/m³

Acceleration due to gravity, g = 9.8 m/s²

Now,

The total mass of the cone (m) = Density of the cone × volume of the cone

Volume of the cone = \frac{1}{3}\pi r^2 h

thus,

volume of the cone = \frac{1}{3}\pi 1.2^2\times 4 = 6.03 m³

therefore, the mass of the cone = 600 Kg/m³ × 6.03 m³ = 3619.11 kg

The center of mass for the cone lies at the \frac{1}{4}times the total height

thus,

center of mass lies at,  h' = \frac{1}{4}\times4=1m

Now, the work gone (W) against gravity is given as:

W = mgh'

W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J

4 0
4 years ago
How does electricity flow?
DedPeter [7]
Current flows from High Potential (Positive) to Low potential (Negative)

So, option D is your answer!

Hope this helps!
3 0
4 years ago
Read 2 more answers
The display of the aurora and the reflection of radio waves back to earth result from the _____.
Tasya [4]

The layer of electrically charged molecules and atoms which spans 40-250 miles above ground called ionosphere causes the display of the aurora and the reflection of radio waves back to earth.

8 0
4 years ago
Read 2 more answers
In which object more force has to be applied to move in between two objects of mas 11
jeka94

Answer:

my butt

Explanation:

2x2 by the power of 10 divide that 98

4 0
3 years ago
A 10-cm-long wire is pulled along a u-shaped conducting rail in a perpendicular magnetic field. the total resistance of the wire
Debora [2.8K]

In the above case we can say that power given by external agent to pull the rod must be equal to the power dissipated in the form of heat due to magnetic induction.

Part a)

when we pull the rod with constant speed then power required will be product of force and velocity

here we will have

P = F.v

P = 4 W

v = 4 m/s

now we will have

4 = F*4

F = 1N

So external force required will be 1 N

PART B)

now in order to find magnetic field strength we can say

P = \frac{v^2B^2L^2}{R}

here we know that induced EMF in the wire is E = vBL

so power due to induced magnetic field is given by

P = \frac{E^2}{R}

4 = \frac{4^2*B^2*0.10^2}{0.20}

by solving above equation we will have

B = 2.24 T

5 0
3 years ago
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