Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Answer 1

Answer: 0.25M

Explanation:

Molarity : It is defined as the number of moles of solute present in one liter of solution.

$Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is L}}$

Given mass of  $H_2SO_4$ = 73.5 g

Molar mass of $H_2SO_4$ = 98g/mol

Volume of solution = 3.0L

$Molarity=\frac{73.5g}{98g/mol\times 3L}=0.25M$

Answer 2

Molar mass H2SO4 = 98 g/mol

number of moles:

73,5 / 98 => 0.75 moles

Volume = 3.0 L

M = n / V

M = 0.75 / 3.0

M = 0.25 mol/L

hope this helps!