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yarga [219]
3 years ago
6

Write a thermodynamic equation for

Chemistry
1 answer:
alexandr1967 [171]3 years ago
8 0

Explanation:

kJ mol^-1

a) = 1681.06

b) = 1450.68

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Select the correct answer
vekshin1

Answer:

Temperature

Explanation:

Kinetic energy of gass molecules is directly propotional to the temperature.

4 0
3 years ago
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25 Points Please Help ASAP!! View Attached Image!! Will Mark Brainliest If All Are Answered!!
KIM [24]

Answer:

Answers in explanation.

Explanation:

30. A (A chemical changes changes the chemical properties)

31. C (rusting is an example of a chemical change

32. B (A reaction requires energy, so some energy will be expelled)

33. B (Color change is an example of a chemical change)

34. A (The law of the conservation of mass: Mass and Energy cannot be created nor destroyed)

8 0
3 years ago
Metals are found on the left-hand side of the periodic table. True or False
Tanya [424]

Answer:

true pls mark brainiest

Explanation:

5 0
3 years ago
A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is
IRINA_888 [86]

Answer:

no. of water molecules associated to each molecule of MnCl_2 = 4

Explanation:

Mass of MnCl_2 before heating = 19.8 g

Mass of MnCl_2 after heating = 12.6 g

Difference in mass of MnCl_2 before and after heating

                                 = 19.8 - 12.6 = 7.2 g

Difference in mass corresponds to mass of water driven out.

Molar mass of water = 18 g/mol

No. of moles of water = \frac{7.2}{18} = 0.4\ mol

Mass of MnCl_2 obtained after heating is mass of anhydrous MnCl_2.

Mass of anhydrous MnCl_2 = 12.6 g

Molar mass of MnCl_2 = 125.9 g/mol

No. of mol of anhydrous MnCl_2 = \frac{125.9}{125.9} = 0.1\ mol

so,

0.1 mol of MnCl_2 have 0.4 mol of water

1 mol of MnCl_2 will have = \frac{0.4}{0.1} =4\ mol

Hence, no. of water molecules associated to each molecule of MnCl_2 = 4

5 0
3 years ago
In the uncatalyzed reaction N2O4 (g) ⇌ 2 NO2 (g) the pressure of the gases at equilibrium are PN2O4 = 0.377 atm and PNO2 = 1.56
larisa86 [58]

Answer:

The pressures will remain at the same value.

Explanation:

A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the or slows down the rate of a chemical reaction.

While a catalyst affects the rate, it is noteworthy that it has no effect on the equilibrium position of the chemical reaction. A catalyst works by creating an alternative pathway for the reaction to proceed. Most times, it decreases the activation energy needed to kickstart the chemical reaction.

Hence, we know that it has no effect on the equilibrium position. Factors affecting equilibrium position includes, temperature and concentration of reactants and products( pressure in terms of gases).

The reactants and the products here are gaseous, and as such pressure affects the equilibrium position. Now, we have established that the equilibrium position is unaffected. And as such the pressure affecting it does not change.

Thus, we have established that the pressure of the products and reactants are unaffected and as such they remain at their value unaffected.

8 0
3 years ago
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