H₂SO₃ is weaker acid than H₂SO₄.
The bonding power of an acid is typically influenced by the size of the "SO₄" atom; the smaller the "SO₄" atom, the stronger the H-A bond. The atoms get larger and the bonds get weaker as you proceed down a row in the Periodic Table, strengthening the acids.
<h3>Describe acid.</h3>
The term "acid" refers to any molecule or ion that can donate a proton (a Brnsted-Lowry acid) or establish a covalent bond with an electron pair (a Lewis acid). The first class of acids is the proton donors, also known as Brnsted-Lowry acids.
Its chemical name is lysergic acid diethylamide, or LSD as it is more often known. Because it has a potent hallucinogenic impact, using it could alter how you see the world and its objects. The effects of LSD are referred to as tripping.
The term "acid" is frequently used to denote aqueous solutions of acids with a pH lower than 8, even though the technical meaning of the term only pertains to the solute.
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Answer:
See Explanation
Explanation:
Ionization energy refers to the energy required to remove an electron from an atom. Metals have lower ionization energy than non metals since ionization energy increases across a period.
One thing that we must have in mind is that it takes much more energy to remove an electron from an inner filled shell than it takes to remove an electron from an outermost incompletely filled shell.
Now let us consider the case of magnesium which has two outermost electrons. Between IE2 and IE3 we have now moved to an inner filled shell(IE3 refers to removal of electrons from the inner second shell) and a lot of energy is required to remove an electron from this inner filled shell, hence the jump.
For aluminium having three outermost electrons, there is a jump between IE3 and IE4 because IE4 deals with electron removal from a second inner filled shell and a lot of energy is involved in the process hence the jump.
Hence a jump occurs each time electrons are removed from an inner filled shell.
The empirical formula is XeO₃.
<u>Explanation:</u>
Assume 100 g of the compound is present. This changes the percents to grams:
Given mass in g:
Xenon = 73.23 g
Oxygen = 26.77 g
We have to convert it to moles.
Xe = 73.23/
131.293 = 0.56 moles
O = 26.77/ 16 = 1.67 moles
Divide by the lowest value, seeking the smallest whole-number ratio:
Xe = 0.56/ 0.56 = 1
O = 1.67/ 0.56 = 2.9 ≈3
So the empirical formula is XeO₃.
Answer : The correct answer is 2.36 mol of gold
1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).
So the formula relating mole and number of atoms is given as :
Plugging value in formula :
Mole of gold = 2.36 mol
