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sasho [114]
3 years ago
11

A cube, 1 m on each edge, is held 0.75 m below the surface of a pool of water by a rope. The mass of the cube is 700 kg, and the

weight distribution is such that one face remains parallel to the surface of the water. a. Find the tension in the rope. b. Assuming the rope is cut, how far will the cube protrude from the water
Physics
1 answer:
meriva3 years ago
8 0

Answer:

Explanation:

The mass of cube = 700 kg

volume = 1 m³

density = 700 kg / m²

Its density is less than that of water so it will try to float on the surface .

Tension in rope will be equal to net upward force

upthrust = volume x density of water x g

= 1 x 10³ x 9.8

= 9800 N

weight of cube = mass x g

= 700 x 9.8

= 6860 N .

Net upward force = 9800 - 6860

= 2940 N.

Tension in the rope = 2940 N.

Rope will hold the cube inside and not allow it to go outside water .

b )

If rope is cut , cube being lighter , will float on surface of water .

Part of cube inside water while floating

= 6860 / 9800

= .7

.7 m will remain inside water

part floating outside

= 1 - 0.7

= 0.3 m .

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3 years ago
A wire carries a current of 10 amps in a direction of 90 degrees with respect to the direction of an external magnetic field of
Oksi-84 [34.3K]

Answer:

15 N

Explanation:

The magnetic force on a piece of current-carrying wire is given by:

F=ILB sin \theta

where

I is the current in the wire

L is the length of the piece of wire

B is the magnetic field strength

\theta is the angle between the direction of B and I

In this problem:

I = 10 A

B = 0.3 T

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\theta=90^{\circ}

Substituting into the equation, we find

F=(10 A)(0.3 T)(5 m) sin 90^{\circ}=15 N

6 0
3 years ago
A rod of 2.0-m length and a square (2.0 mm × 2.0 mm) cross section is made of a material with a resistivity of 6.0 × 10–8 Ω ⋅ m.
Andrews [41]

Answer:

= 8.33 Watt

Explanation:

R = \frac{pl}{A}

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p = resistivity

l = length

A = cross section area

Given that ,

p = resistivity = 6.0 × 10–8 Ω

l = 2m

A = cross section area = 2.0 mm × 2.0 mm = 4 x 10^-6 m^2

A = 2 x 2 mm^2 = 4 x 10^-6 m^2

p = 6 x 10^-8 ohm metre,

V = 0.5 V

Let R be the resistance of the rod

R = p\frac{l}{A} \\\\R = 6.0 \times 10^-^8 (\frac{2}{4 \times 10^-^6} )\\\\R = 3 \times 10^-^2

R = 3 × 10⁻²Ω

Heat generated  = V^2 / R

= (0.5)^2 / (3 x 10^-2)

 = 8.33 Watt

5 0
3 years ago
A crane does 62,500 joules of work to lift a boulder a distance of 25.0 meters. How much did the boulder weight
alukav5142 [94]
Work = (force) x (distance)

62,500 joules = (boulder's weight) x (25 meters)

Divide each side by (25 meters) :

Boulder's weight = (62,500 joules) / (25 meters) = <u>2,500 newtons</u>

That's about 562 pounds.
7 0
3 years ago
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