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cricket20 [7]
3 years ago
11

Septum: Left and right atrium: Pacemaker: Left and right ventricles: Valves:

Physics
1 answer:
hammer [34]3 years ago
4 0
Can you define the question further.

This may help with your answer:

Tricuspid valve. This valve is located between the right atrium and the right ventricle.
Pulmonary valve. The pulmonary valve is located between the right ventricle and the pulmonary artery.
Mitral valve. This valve is located between the left atrium and the left ventricle. It has only 2 leaflets.
Aortic valve. The aortic valve is located between the left ventricle and the aorta
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What components must be built to create hydroelectric power?
sergeinik [125]
Turbine transformer generator⇆
3 0
3 years ago
Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba
Aneli [31]
Answer:
180 meters

Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters

Based on the above calculations, Josh walks 180 meters over the course of the class

Hope this helps :)
3 0
3 years ago
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen sp
Colt1911 [192]

Answer:

λ = 396.7 nm

Explanation:

For this exercise we use the diffraction ratio of a grating

           d sin θ = m λ

in general the networks works in the first order m = 1

we can use trigonometry, remembering that in diffraction experiments the angles are small

           tan θ = y / L

           tan θ = \frac{sin \theta}{cos \theta} = sin θ

           sin θ = y / L

we substitute

          d \  \frac{y}{L} = m λ

with the initial data we look for the distance between the lines

           d = \frac{m \lambda \ L}{y}

           d = 1 656 10⁻⁹ 1.00 / 0.600

            d = 1.09 10⁻⁶ m

for the unknown lamp we look for the wavelength

           λ = d y / L m

           λ = 1.09 10⁻⁶ 0.364 / 1.00 1

           λ = 3.9676 10⁻⁷ m

           λ = 3.967 10⁻⁷ m

         

we reduce nm

           λ = 396.7 nm

8 0
3 years ago
Out of hypothesis, theories and laws “can help predict future events”
Amanda [17]

Answer:

true

Explanation:

7 0
3 years ago
Q.01 When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False
Nitella [24]

True, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.

<h3>Relationship between dielectric material and electric field</h3>

The electric field in a capacitor separates the negative and positive charges in the dielectric material, this causes an attractive force between each plate and the dielectric.

The dielectric material can store electric energy due to its polarization in the presence of external electric field, which causes the positive charge to store on one electrode and negative charge on the other.

Thus, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.

Learn more about dielectric material here: brainly.com/question/17090590

4 0
2 years ago
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