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GREYUIT [131]
3 years ago
8

Do solids flow and how do they do that

Physics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

No they will not

Explanation: they are soli

Eva8 [605]3 years ago
7 0

Answer:

solids cannot flow because the molecules a held tightly together

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Is gravity a non-contact form?
sattari [20]
No, we cannot touch gravity nor can we physically see it. We can only see how it works.
8 0
3 years ago
If a car used 260.000 W of power to complete a race in 15 s. how much work did the car do?
marta [7]

Work done by the car is 3900 J

Explanation:

  • Power and work are related by the equation, Power = Work Done/Time
  • Power is the rate at which work is done.
  • Here, the car uses power of 260 W and time taken is 15 s.

Work Done = Power × Time

                   = 260 × 15 = 3900 J

3 0
3 years ago
I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t
dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where L is the length of the string, T the tension and m its mass. If  we plug the data of the problem into the equation, we find
f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz

The wavelength of the standing wave is instead twice the length of the string:
\lambda=2 L= 2 \cdot 24 m=48 m

So the speed of the wave is
v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s
7 0
3 years ago
If you used 16 gallons when driving 367 miles, what was your gas mileage over that distance
White raven [17]
Your gas mileage would be 22.93 miles per gallon.
6 0
3 years ago
A force Fx=cx-3.00x2 acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c a consta
andrey2020 [161]

Answer:

4

Explanation:

We are given that

F_x=cx-3x^2

K.E at x=0 m=20 J

K.E at x=3 m=11 J

We have to find the value of c.

By work energy theorem

Work done=Change in kinetic energy

W=\int_{0}^{3} Fdx=\int_{0}^{3}(cx-3x^2)dx

W=[\frac{cx^2}{2}-x^3]^{3}_{0}

W=\frac{9c}{2}-27

\Delta K=11-20=-9 J

-9=\frac{9c}{2}-27

-9+27=\frac{9c}{2}

18=\frac{9c}{2}

c=\frac{2}{9}\times 18=4

4 0
3 years ago
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