Answer:
d)
Explanation:
Electrons are lost or gained when the ballon is rubbed with a PVC. As the rubber ballon lost electrons, it will have more protons, hence the positive charge. (More protons than electrons in the ballon).
Your answer is 2.5 x 10^(11).
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Answer:
largest lead = 3 m
Explanation:
Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.
So, first we need to calculate the velocities of both the anchorman
given data:
Distance = d = 100 m
Time arrival for A = 9.8 s
Time arrival for B = 10.1 s
Velocity of anchorman A = D / Time arrival for A
=100/ 9.8 = 10.2 m/s
Velocity of anchorman B = D / Time arrival for B
=100/10.1 = 9.9 m/s
As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use
d = vt
= 9.9 x 9.8 = 97 m
So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.
largest lead = 100 - 97 = 3 m
So if his lead no more than 3 m anchorman A win the race.
Average speed is the ratio of total distance moved by Chi in total time interval
So here we will have
Total distance = 100 m + 400 m
![d = 500 m = 0.5 km](https://tex.z-dn.net/?f=d%20%3D%20500%20m%20%3D%200.5%20km)
Total time taken = 5 min + 15 min = 20 min
![T = \frac{20}{60} = \frac{1}{3} hour](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B20%7D%7B60%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20hour)
now by the formula of average speed we know that
![v_{avg} = \frac{d}{T}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7Bd%7D%7BT%7D)
![v_{avg} = \frac{0.5 km}{1/3 h}](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7B0.5%20km%7D%7B1%2F3%20h%7D)
![v_{avg} = 1.5 km/h](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%201.5%20km%2Fh)
so average speed will be 1.5 km/h
1). c ... 2). d ... 3). a ... 4). d ... 5). c ... 6). a
7). b-mass ... c-m/s ... d-Newton's 1st ... e-Newton's 2nd