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il63 [147K]
4 years ago
11

According to the VSEPR model, the progressive decrease in the bond angles in the series of molecules CH₄, NH₃, and H₂O is best a

ccounted for by the _________.
Chemistry
1 answer:
bonufazy [111]4 years ago
5 0

Answer:

lone pair-bond pair repulsion is best accounted for decrease in bond angle

Explanation:

Bond angle in each compounds depends on presence of lone pair on central atom.

In CH_{4}, there is no lone pair on C atom. So, no lone pair-bond pair repulsion is present here. Hence \angle H-C-H is 109^{0}5^{'}

In NH_{3}, there is one lone pair on N atom. So, one lone pair-bond pair repulsion is present here. Hence \angle H-N-H is 107^{0}

In H_{2}O, there are two lone pairs on O atom. So, two lone pair-bond pair repulsion are present here. Hence \angle H-O-H is 104^{0}5^{'}

So, lone pair-bond pair repulsion is best accounted for decrease in bond angle

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How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
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Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

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For first-order kinetics, we will use the following expression.

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