Answer:
V = 134.5 L
Explanation:
Given data:
Number of moles of KClO₃ = 4 mol
Litters of oxygen produced at STP = ?
Solution:
Chemical equation:
2KClO₃ → 2KCl + 3O₂
Now we will compare the moles of KClO₃ with oxygen.
KClO₃ : O₂
2 : 3
4 ; 3/2×4 = 6 mol
Litters of oxygen at STP:
PV = nRT
V = nRT/P
V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm
V = 134.5 L / 1
V = 134.5 L
Organic chemistry present for a substance
Answer:
Total gram of Ca = 99.26 g
Explanation:
Given:
Mass of CaCl₂ = 277.45 g
Find:
Mass of Ca
Computation:
Ca = 40 g/mol
Cl₂ = 2 (35.5) g/mol = 71 g/mol
Total CaCl₂ = 111 g/mol
Total gram of Ca = [40 / 111] 277.45 g
Total gram of Ca = 99.26 g
you could easily search this on Google but it's 0.004312.
1000000 Cubic Meter is 1 cubic centimeter.
but if there is 4312, do 4312/10000000..
