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2 years ago

What is a Chemical Properties and Physical Properties? Please tell me the deffinition of them both.

Chemistry

1 answer:

Pavlova-9 [17]2 years ago

3 0

Answer:

All properties of matter are either physical or chemical properties and physical properties are either intensive or extensive. ... Physical properties can be measured without changing a substance's chemical identity. Chemical properties can be measured only by changing a substance's chemical identity.

Explanation:

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A runner wants to run 10.4 km k m . She knows that her running pace is 8.0 mi/h m i / h .

mars1129 [50]

Answer:

Approximately 49 minutes.

Explanation:

1 mile = 1.6 km

So 8.0 x 1.6 km

Minutes required: $\frac{10.4 times 60 }{8.0 times 1.6}$ = 48.75 minutes

I hope this helped :)

4 0

3 years ago

2. Name three factors that influence the rate at which a solute dissolves in a solvent?<br>

agasfer [191]

Answer:

1. Temperature

2. Surface area

3. Catalyst

Explanation:

3 0

3 years ago

Read 2 more answers

if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa

bija089 [108]

Answer:

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂ Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂

p₁ = 485 kPa; V₁ = 648 mL

p₂ = ?; V₂ = 0.15 L = 150 mL Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa

4 0

3 years ago

Consider the reaction of ruthenium(III) iodide with carbon dioxide and silver. RuI3 (s) 5CO (g) 3Ag (s) Ru(CO)5 (s) 3AgI (s) Det

mixer [17]

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

8 0

3 years ago

Rank the ions in each set in order of increasing size, and explain your ranking:

Paha777 [63]

Explanation:

Lithium, sodium and potassium are all group 1A elements and when we move down a group then there occurs an increase in atomic size of the elements. As lithium is the smallest and potassium being the largest so, when each of them will lose an electron and obtain a positive charge then size of lithium will further decrease.

Therefore, ions are ranked according to their increase in size as follows.

$Li^{+} < Na^{+} < K^{+}$

When an atom tends to gain electrons then it acquires a negative charge. This means that size of the atom increases.

So, more is the negative charge present on an atom more will be its atomic size. Therefore, correct order of increasing size for $Se^{2-}, Rb^{+}, Br$ is as follows.

$Br < Rb^{+} < Se^{2-}$

Similarly, order of increasing size of $O^{2-}, F^{-}, N^{3-}$ is as follows.

$F^{-} < O^{2-} < N^{3-}$

5 0

3 years ago