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lianna [129]
4 years ago
11

We introduce an electron in a homogeneous electric field. Can we have a net torque on the electron? Please explain.

Physics
1 answer:
Stels [109]4 years ago
6 0

Answer:

  No

Explanation:

As we know that force on charge given as

F = q E

E=Electric filed

F=Force

q=Charge

Torque = Force x Distance between force

For producing torque two charge is required one single charge can not produce torque.So when we placed an electron in homogeneous field then it did not experience any net torque.

So answer is No.

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Water of mass, m at 100 ℃ is added to 0.50 kg of water at 20 ℃ in a lagged calorimeter of thermal capacity 105 JK −1 . If the sp
lorasvet [3.4K]

The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

<h3>Determine the value of m </h3>

Applying the principle of energy conservation

Heat lost by the hot body = heat absorbed by the cold water + calorimeter

= m * 4200 * ( 100 - 70  ) = 0.50 * 4200 * ( 70 -20 ) + 105 * ( 70 -20 )

= m * 126000 = 110250

therefore ;

m = 110250 / 126000

  = 0.875 kg

Hence we can conclude that The value of m given that the temperature of the mixture is 70°C is : 0.875 Kg

Learn more about specific heat capacity : brainly.com/question/10541586

8 0
2 years ago
The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m
Julli [10]

Answer:

v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m

Let us assume we need to find its velocity.

We know that,

v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

So, the velocity of the particle is (6ti+6k)\ m/s.

5 0
3 years ago
A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is
pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

v = u + at

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0
3 years ago
determine the weight in newtons of a woman whose weight in pounds is 125. also, find her mass in slugs and in kilograms. DEtermi
xxMikexx [17]

Answer:

124 just subtract only one

Explanation:

4 0
3 years ago
PLEASE HELP I NEED TO TURN IT IN IN AN HOUR ITLL GIVE YOU POINTS PLS PLEASE
miv72 [106K]

Answer:

  1. 17.95025
  2. 172.3995

Explanation:

1.

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{2.995}{0.16685}\:\\\mathrm{is}\:17.95025

2.

\mathrm{Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer}\\\\910\times\:18945=17239950\\\\910\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\0.18945\mathrm{\:has\:}5\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}5\mathrm{\:decimal\:places}\\\\=172.39950\\\\Refine\\=172.3995

5 0
3 years ago
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