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3 years ago

We introduce an electron in a homogeneous electric field. Can we have a net torque on the electron? Please explain.

Physics

1 answer:

Stels [109]3 years ago

6 0

Answer:

Explanation:

As we know that force on charge given as

F = q E

E=Electric filed

F=Force

q=Charge

Torque = Force x Distance between force

For producing torque two charge is required one single charge can not produce torque.So when we placed an electron in homogeneous field then it did not experience any net torque.

So answer is No.

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When a layer of cold air close to the ground is covered by a layer of warmer air, sound waves traveling upward may be bent, or refracted, by the difference in temperature and redirected toward the ground.

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2 years ago

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An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the

Aleksandr-060686 [28]

Answer:

i). Inverted

ii). Magnification of the image = -0.5

iii). Real

Explanation:

As shown in the ray diagram attached,

An object AB has been placed in front of converging lens (convex lens) at u = 30 cm.

F (Focus) of the lens is at 10 cm. So F = 10 cm

By analyzing the ray diagram we can measure the distance of the image on the other side of the lens (By counting the small blocks of the graph)

V = 15 cm

Characteristics of the image is:

i) Inverted

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= -0.5

ii) Real

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3 years ago

A spring has a spring constant of 20 N/m. How much potential energy is stored in the spring as it stretched 0.20 m

makkiz [27]

The elastic potential energy (Ep) is given by $Ep = \frac{1}{2}*k*x^2$

Data:
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m

Solving:
$Ep = \frac{1}{2}*k*x^2$
$Ep = \frac{1}{2}*20*0.20^2$
$Ep = \frac{20*0.04}{2}$
$Ep = \frac{0.8}{2}$
$\boxed{\boxed{Ep = 0.4\:J}}\end{array}}\qquad\quad\checkmark$

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3 years ago

What is the acceleration of a 50 kg object pushed with a net force of 500 newtons?

vodomira [7]

Using the formula F=ma
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3 years ago

The earth has radius R. A satellite of mass 100 kg is in orbit at an altitude of 3R above the earth's surface. What is the satel

Vera_Pavlovna [14]

Answer:

W= 61.3 N

Explanation:

The only force acting on the satellite is the one due to the attraction from Earth, which obeys the Newton's Universal Law of Gravitation, as follows:

Fg =G*ms*me / (res)²

This force, also obeys the Newton's 2nd Law, so we can write the following equation:

G*ms*me*/ (res)² = ms* a = ms*g

We call to the product of the mass times the acceleration caused by gravity (g), the weight of this mass, so we can write as follows:

G*ms*me / (res)² = ms*g = W (1)

where G = 6.67*10⁻11 N*m²/kg², ms= 100 kg, me= 5.97*10²⁴ kg, and

res= 4 *re = 4*6.37*10⁶ m.

Replacing all these known values in (1), we get the value of W:

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6 0

3 years ago