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3 years ago

We introduce an electron in a homogeneous electric field. Can we have a net torque on the electron? Please explain.

Physics

1 answer:

Stels [109]3 years ago

6 0

Answer:

Explanation:

As we know that force on charge given as

F = q E

E=Electric filed

F=Force

q=Charge

Torque = Force x Distance between force

For producing torque two charge is required one single charge can not produce torque.So when we placed an electron in homogeneous field then it did not experience any net torque.

So answer is No.

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How much work is done when a 5 N force moves a block 4 m?

katen-ka-za [31]

20N•m or 20J. Work is equal to force•distance, and 5N•4m is 20N•m, or J

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3 years ago

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.7 m tall window in 0.129 sec. From how high above th

vladimir1956 [14]

Answer:

h = 22.35 m

Explanation:

given,

initial speed of the rock,u = 0 m/s

length of the window,l = 2.7 m

time taken to cross the window,t = 0.129 s

Speed of the rock when it crosses the window

$v = \dfrac{l}{t}$

$v = \dfrac{2.7}{0.129}$

v = 20.93 m/s

height of the building above the window

using equation of motion

v² = u² + 2 g h

20.93² = 0² + 2 x 9.8 x h

h = 22.35 m

Hence, the height of the building above the top of window is equal to h = 22.35 m

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3 years ago

A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i

andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

Determine the oscillation period

at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93

note : w = $\sqrt{k/m}$ = $\sqrt{337.93}$ = 18.38 rad/sec

Period of oscillation = $2\pi / w$

= 0.34 sec

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3 years ago

Describe three ways you can conserve energy in your own home

Mandarinka [93]

Turn lights off, unplug electronics, and use solar energy

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3 years ago

Read 2 more answers

A car drives at steady speed around a perfectly circular track.

gayaneshka [121]

Answer:

e. Both the acceleration and net force on the car point inward.

Explanation:

If no net force acts on the car, the car must drive in a straight line, at constant speed.

As the acceleration is defined as the rate of change of the velocity vector, this means that it can produce either a change in the magnitude of the velocity (the speed) or in the direction.

In order to the car can follow a circular trajectory, it must be subjected to an acceleration, that must go inward, trying to take the car towards the center of the circle.

The net force that causes this acceleration, aims inward, and is called the centripetal force.

It is not a different type of force, it can be a friction force, a tension force, a normal force, etc., as needed.

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4 years ago