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2 years ago

How does velocity change in a circular motion

Physics

1 answer:

djverab [1.8K]2 years ago

6 0

Explanation:

For an object to maintain circular motion it must constantly change direction. Since velocity is a vector, changes in direction constitute changes in velocity. A change in velocity is known as an acceleration. The change in velocity due to circular motion is known as centripetal acceleration.

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11. What are mechanical waves caused by?

Rzqust [24]

Answer: mechanical waves are caused by the disturbance of vibration in matter, whether solid, gas, liquid, or plasma.

Explanation:

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2 years ago

A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70

JulijaS [17]

Answer:

a = 580 m/s^2

Explanation:

Given:

- Distance for accelerated throw s_a = 70 cm

- Angle of throw Q = 30 degrees

- Distance traveled by the javelin in horizontal direction x(f) = 75 m

- Initial height of throw y(0) = 0

- Final height of the javelin y(f) = -2 m

Find:

What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Solution:

- Compute initial components of the velocity:

V_x,i = V*cos(30)

V_y,i = V*sin(30)

- Use second equation of motion in horizontal direction:

x(f) = x(0) + V*cos(30)*t

75 = 0 + V*cos(30)*t

t = 75 /V*cos(30)

- Use equation of motion in vertical direction:

y(f) = y(0) + V_y,i*t + 0.5*g*t^2

Subs the values:

-2 = 0 + V*sin(30)*75/V*cos(30) - 4.905*(75/Vcos(30))^2

-2 = 75*tan(30) - 4.905*(5625/V^2*cos^2(30))

V^2 = 4.905*5625 / (2 + 75*tan(30))*cos^2(30)

V^2 = 812.0633

V = 28.5 m/s

- Use the third equation of motion in the interval of the throw:

V^2 = U^2 + 2*a*s_a

28.5^2 = 2*a*0.7

a = 580 m/s^2

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2 years ago

Take the following measured gauge (or gage) pressures and convert them to absolute pressures in both kPa and psi units for an am

mamaluj [8]

Answer:

Explanation:

Given

ambient Pressure =98.10 kPa

(a)gauge pressure 152 kPa

we know

Absolute pressure=gauge pressure+Vacuum Pressure

$P_{abs}$ =152+98.10=250.1 kPa or 36.27 psi

(b) $P_{gauge}$ =67.5 Torr or 8.99 kpa

as 1 Torr is 0.133 kPa

$P_{abs}$ =8.99+98.10=107.09 kPa or 15.53 psi

Thus absolute pressure=98.10-10=88.10 kPa or 12.77 psi

as 1 kPa is equal to 0.145 psi

(d) $P_{vaccum}$ =0.84 atm or 85.113 kPa

as 1 atm is equal to 101.325 kPa

$P_{abs}$ =98.10-85.11=12.99 kPa or 1.88 psi

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2 years ago

What’s a educated guess supported by evidence?

Sauron [17]

a hypothesis is an educated guess :)

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2 years ago

Read 2 more answers

A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o

dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is $m_1 = 81.14 \ kg$

Explanation:

From the question we are told that

Mass of the first block is $m_1 = 100 \ kg$

The height is $s = 1.0 \ m$

The time it takes it is $t = 1.40 \ s$

Generally from kinematic equation

$s = ut + \frac{1}{2} at^2$

Here u is the initial velocity which zero given that it was at rest initially

$s = 0 * t + \frac{1}{2} at^2$

=> $s = \frac{1}{2} at^2$

=> $1 = \frac{1}{2}* a * (1.40 )^2$

=> $a = 1.0204 \ m/s^2$

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is mathematically represented as

$mg - T = ma$

=> $T = m g - ma$

=> $T = m(g - a)$

=> $T = 877.96 \ N$

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is mathematically represented as

$T - m_1g = m_1 a$

=> $877.96 = m_1 (a + g)$

=> $877.96 = m_1 (1.0204 + 9.8 )$

=> $m_1 = 81.14 \ kg$

5 0

2 years ago

How does velocity change in a circular motion​

How does velocity change in a circular motion