Ask question

Ask question

All categories

igor_vitrenko [27]

3 years ago

5

how does the strength of the forces that hold the basic particles of a substance together relate to the temperature at which the

substance changes state

1 answer:

Elan Coil [88]3 years ago

3 0

Answer:

stronger forces between particles means the substance boils at a higher temperature.

Explanation:

A.pex

You might be interested in

Two blocks of masses 20 kg and 8.0 kg are connected togetherby

Dmitry [639]

Answer:

The tension is 14 N

Explanation:

For this problem we have to use newton's law, so:

$F=m*a$

The second string is connected to the mass of 8 kg, but the mass of 8 kg is connected to the mass of 20kg, so we can say that the second string is handling the two masses. so:

$F=28kg*0.5\frac{m}{s^2}=14N$

3 0

3 years ago

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is r

atroni [7]

(a) $2.79 rev/s^2$

The angular acceleration can be calculated by using the following equation:

$\omega_f^2 - \omega_i^2 = 2 \alpha \theta$

where:

$\omega_f = 20.0 rev/s$ is the final angular speed

$\omega_i = 11.0 rev/s$ is the initial angular speed

$\alpha$ is the angular acceleration

$\theta=50.0 rev$ is the number of revolutions made by the disk while accelerating

Solving the equation for $\alpha$ , we find

$\alpha=\frac{\omega_f^2-\omega_i^2}{2d}=\frac{(20.0 rev/s)^2-(11.0 rev/s)^2}{2(50.0 rev)}=2.79 rev/s^2$

(b) 3.23 s

The time needed to complete the 50.0 revolutions can be found by using the equation:

$\alpha = \frac{\omega_f-\omega_i}{t}$

where

$\omega_f = 20.0 rev/s$ is the final angular speed

$\omega_i = 11.0 rev/s$ is the initial angular speed

$\alpha=2.79 rev/s^2$ is the angular acceleration

t is the time

Solving for t, we find

$t=\frac{\omega_f-\omega_i}{\alpha}=\frac{20.0 rev/s-11.0 rev/s}{2.79 rev/s^2}=3.23 s$

(c) 3.94 s

Assuming the disk always kept the same acceleration, then the time required to reach the 11.0 rev/s angular speed can be found again by using

$\alpha = \frac{\omega_f-\omega_i}{t}$

where

$\omega_f = 11.0 rev/s$ is the final angular speed

$\omega_i = 0 rev/s$ is the initial angular speed

$\alpha=2.79 rev/s^2$ is the angular acceleration

t is the time

Solving for t, we find

$t=\frac{\omega_f-\omega_i}{\alpha}=\frac{11.0 rev/s-0 rev/s}{2.79 rev/s^2}=3.94 s$

(d) 21.7 revolutions

The number of revolutions made by the disk to reach the 11.0 rev/s angular speed can be found by using

$\omega_f^2 - \omega_i^2 = 2 \alpha \theta$

where:

$\omega_f = 11.0 rev/s$ is the final angular speed

$\omega_i = 0 rev/s$ is the initial angular speed

$\alpha=2.79 rev/s^2$ is the angular acceleration

$\theta=?$ is the number of revolutions made by the disk while accelerating

Solving the equation for $\theta$ , we find

$\theta=\frac{\omega_f^2-\omega_i^2}{2\alpha}=\frac{(11.0 rev/s)^2-0^2}{2(2.79 rev/s^2)}=21.7 rev$

4 0

3 years ago

The moment of a force is calculated from the product of the ———— and the———— distance from the line of action of the force to th

bixtya [17]

Answer: It is the product of the (force)multiplied by the (perpendicular) distance from the line of action of the force to the pivot

Explanation:

7 0

3 years ago

Which of the following describe an electric motor?

eimsori [14]

Answer:

C. Changes mechanical energy to electrical

7 0

3 years ago

Please Help Me I will try and give extra points if I can and if you have the rest of the answers to this then please help me out

stepan [7]

First, you must know that the statement "<span>An object at rest tends to stay at rest. An object in motion tends to stay in motion unless acted upon by an outside force." is true, because it is the first Law of Newton or inercy law.

what outside force acts on a baseball when it is thrown straight like a pitcher pitching a ball?

After the ball leaves the pitcher's hand, it is subject only to the gravitational attraction of the Earth. That is why the pitcher has to give the appropiate impulse in order to the ball reaches the point that he and the catcher want.

What about if you threw it straight into the air?

It is the same thing. The only force would be the gravitational attraction of the Earth.

What about if you threw the baseball in outer space. Would there be any forces to slow that down?

In outer space, at the beginning the baseball would be very far from of other massive objects to feel their gravitational field, so there would not be any forces to slow it down. Although eventulally, after many light-years, it would enter the gravitational field of a galaxy or other massive body and it would attract it.
</span>

7 0

3 years ago