The answer is salt water.
Salt water can conduct electricity or we can say that an electric current is conducted by salt water as salt water is a good conductor of electricity when salt that is sodium chloride or NaCl is dissolved in water , positively charged sodium (Na⁺) and negatively charged chlorine(Cl⁻) molecules are set apart by the water molecule so that they can float easily and freely. We can define the conductivity of a substance as the mobility or movement of ions. So as in water, sodium and chlorine are set apart and can move freely so it become a electrolyte that can conduct electricity.
<u>Answer:</u> The equation is given below.
<u>Explanation:</u>
Single replacement reactions are the chemical reactions in which more reactive metal displaces a less reactive metal from its chemical reaction. General equation for these reactions is given by the equation:

Metal A is more reactive than metal B.
The reactivity of metals is judged with the help of reactivity series. In this series, the metals lying above are more reactive than the metals which lie below in the series.
For the reaction of solid lithium metal and nitric acid, the equation follows:

This is a type of single replacement reaction because Lithium (more reactive metal) is replacing Hydrogen (less reactive metal) from the chemical reaction.
Answer:
copper is the only material composed of a single pure substance
Explanation:
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Answer:
174 kPa
Explanation:
Given that,
Initial temperature, T₁ = 25° C = 25+273 = 298 K
Final temperature, T₂ = 225°C = 225 + 273 = 498 K
Initial pressure, P₁ = 104 kPa
We need to find the new pressure. The relation between the temperature and pressure is given by :

So,

or
P₂ = 174 kPa
So, the new pressure is 174 kPa.
You may find bellow the balanced chemical equations.
Explanation:
Molecular equations:
3 Sr(NO₃)₂ (aq) + 2 K₃PO₄ (aq) → Sr₃(PO₄)₂ (s) + 6 KNO₃ (aq)
2 NaOH (aq) + Ni(NO₃)₂ (aq) = Ni(OH)₂ (s) + 2 NaNO₃ (aq)
Ionic equations:
3 Sr²⁺ (aq) + 6 NO₃⁻ (aq) + 6 K⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s) + 6 K⁺ (aq) + 6 NO₃⁻ (aq)
2 Na⁺ (aq) + 2 OH⁻ (aq) + Ni²⁺ (aq) + 2 NO₃⁻ (aq) = Ni(OH)₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)
To get the net ionic equation we remove the spectator ions:
3 Sr²⁺ (aq) + 2 PO₄³⁻ (aq) → Sr₃(PO₄)₂ (s)
2 OH⁻ (aq) + Ni²⁺ (aq) = Ni(OH)₂ (s)
Learn more about:
net ionic equations
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